檢測列表中的元素是否是多字

Question

此代碼可以正常工作，但我不能100％確定它是如何工作的，因爲它在我借用的Python書中。我不明白程序如何檢查是否有多字。還什麼做帶星線意味着

places= ["Home","In-n Out Burger", "John's house", "Santa Monica Pier", "Staples center", "LA Dodgers stadium", "Home"] 
def placesCount(places): 
    multi_word = 0 
    count = 0 
    **while True: 
     place = places[count]** 
     if place == 'LA Dodgers stadium': 
      break 
     **if ' ' in place:** 
      multi_word += 1 
     count += 1 
    return count + 1, multi_word + 1 

placesCount(places) 

Answer 1

的方法檢查列表places一個字符串中有空格，它認爲，一個多字。

如果列表places包含字符串LA Dodgers stadium，該方法將返回字符串的位置，加上在其之前找到多少個多個單詞的計數。

這是一個提示：當你將['LA Dodgers stadium']傳遞給函數時會發生什麼？它會返回正確的數字嗎？

def placesCount(places): 
    multi_word = 0 # a count of how many multiple words were found 
    count = 0 # an initializer (not needed in Python) 
    while True: # start a while loop 
     place = places[count] # get the object from the places list 
           # at position count 
     if place == 'LA Dodgers stadium': 
      # quit the loop if the current place equals 'LA Dodgers stadium' 
      break 
     if ' ' in place: 
      # If the current string from the places list 
      # (which is stored pointed to by the name place) 
      # contains a space, add one to the value of multi_word 
      multi_word += 1 
     # Add one to count, so the loop will pick the next object from the list 
     count += 1 
    # return a tuple, the first is how many words in the list 
    # and the second item is how many multiple words (words with spaces) 
    return count + 1, multi_word + 1 

到位