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我有一個表是這樣的:分組和過濾通過最新時間戳
------------------------------------------------- id | race_id | heat | updated_at ------------------------------------------------- 28952 189 1 2017-06-24 19:57:44.433431 28956 189 1 2017-06-24 20:33:49.984958 28958 189 1 2017-06-24 21:43:59.538041 28953 189 2 2017-06-24 19:57:45.309102 28957 189 2 2017-06-24 20:36:41.725912 28961 189 2 2017-06-24 21:46:39.677080 28954 189 3 2017-06-24 19:57:46.142353 28959 189 3 2017-06-24 21:44:00.651232 28964 189 3 2017-06-24 23:13:24.172765 28969 189 3 2017-06-25 01:01:25.445597 28955 189 4 2017-06-24 19:57:47.056272 28962 189 4 2017-06-24 21:46:40.839643 28965 189 4 2017-06-25 01:00:44.736679 28966 189 4 2017-06-25 01:01:04.010346 28960 189 5 2017-06-24 21:44:02.443140 28963 189 5 2017-06-24 21:46:41.861473 28968 189 6 2017-06-25 01:01:06.028000 28971 189 6 2017-06-25 01:01:28.445862 28967 189 8 2017-06-25 01:01:05.198073 28970 189 8 2017-06-25 01:01:27.533253
但我想按race_id和熱量與各組的最新時間戳。我希望看到這樣的事情:
------------------------------------------------- id | race_id | heat | updated_at ------------------------------------------------- 28958 189 1 2017-06-24 21:43:59.538041 28961 189 2 2017-06-24 21:46:39.677080 28969 189 3 2017-06-25 01:01:25.445597 28966 189 4 2017-06-25 01:01:04.010346 28963 189 5 2017-06-24 21:46:41.861473 28971 189 6 2017-06-25 01:01:28.445862 28970 189 8 2017-06-25 01:01:27.533253
我想使用
select id, race_id, heat, updated_at from heats where race_id = 189 group by race_id, heat having updated_at = max(updated_at) order by heat asc;但我沒有得到任何結果回來。
last_updated = max(last_updated)?你說你有'updated_at'道具 – Alendorff
我的不好,我把它改爲SO – Aaron