將mysql行數據存儲到php變量名稱和值中

Question

我需要幫助將sql查詢中的值存儲到變量中。問題是爲了得到適當的值，我寫了一個很長的UNION查詢。只有兩列，並沒有多少結果。理想情況下，我想爲每行創建一個變量，其中變量名稱是第一列的結果，該變量的相應值將是第二列的結果。

這裏是聯合查詢：

SELECT 'mon_m' as shift, count(mon_m) as count 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND mon_m <> '' 

UNION 

SELECT 'mon_a', COUNT(mon_a) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND mon_a <> '' 

UNION 

SELECT 'mon_n', COUNT(mon_n) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND mon_n <> '' 

UNION 

SELECT 'tue_m', count(tue_m) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND tue_m <> '' 

UNION 

SELECT 'tue_a', COUNT(tue_a) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND tue_a <> '' 

UNION 

SELECT 'tue_n', COUNT(tue_n) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND tue_n <> '' 

UNION 

SELECT 'wed_m', count(wed_m) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND wed_m <> '' 

UNION 

SELECT 'wed_a', COUNT(wed_a) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND wed_a <> '' 

UNION 

SELECT 'wed_n', COUNT(wed_n) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND wed_n <> '' 

UNION 

SELECT 'thu_m', count(thu_m) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND thu_m <> '' 

UNION 

SELECT 'thu_a', COUNT(thu_a) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND thu_a <> '' 

UNION 

SELECT 'thu_n', COUNT(thu_n) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND thu_n <> '' 

UNION 

SELECT 'fri_m', count(fri_m) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND fri_m <> '' 

UNION 

SELECT 'fri_a', COUNT(fri_a) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND fri_a <> '' 

UNION 

SELECT 'fri_n', COUNT(fri_n) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND fri_n <> '' 

UNION 

SELECT 'sat', count(sat) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND sat <> '' 

UNION 

SELECT 'sun', COUNT(sun) 
FROM schedule 
WHERE week_of = '2013-12-23' 
AND sun <> '' 

這裏的數據想什麼小樣本：

ColumnA ColumnB 
mon_m  1 
mon_a  5 
mon_n  6 
tue_m  3 
tue_a  6 
tue_n  2 

我需要使用PHP這樣我就可以建一個表來訪問這些值。我想使用變量訪問它們。例如：

echo $mon_m 
echo $mon_a 
echo $mon_n 

凡

$mon_m = 1 
$mon_a = 5 
$mon_n = 6 

我已經準備好去，需要一些幫助，讓這些值到PHP變量的SQL語句。

Answer 1

一旦你得到了MySQL查詢的結果，可以通過提取

extract($results); 

這將爲陣列中的每個關鍵變量運行它，所以一定要確保你的結果會返回一個關聯數組。有關更多詳細信息，請參閱http://www.php.net/manual/en/function.extract.php。

Answer 2

爲什麼不使用數組？

$output_array = array(
    "mon_m" => 1, 
    "mon_a" => 2, 
    "mon_n" => 3 
); 

然後輸出他們像這樣

echo $output_array['mon_m']; 

而且，你的結果可以更加方便地在這種情況下，MySQL的。

$r = mysql_query("select * from table where columnB=" . $var); 
while($row = mysql_fetch_assoc($r)){ 
    $column = $row['columnA']; 
    $output_array[$column] = $row['columnB']; 
} 

然後你就可以做各種東西，有了它，通過輸出表循環，檢查值，鑰匙等與你提出什麼，我不認爲這將是很容易跟蹤創建的變量，或者與他們一起工作非常容易。

編輯::

這是一個更好的（？）方法來做到這一點。也許格外過於複雜的滿足您的需求，但與意見建議你使用PDO ...

function getObject($sql){ 
    $dbCon = new object(); 
     // building data source name 
     $dsn = 'mysql:host=' . DB_HOST . 
       ';dbname=' . DB_NAME . 
       ';connect_timeout=15'; 

     $dbCon->dbh = new PDO($dsn, DB_USER, DB_PASS); 

    try { 

     $stmt = $dbCon->dbh->prepare($sql); 

     $stmt->setFetchMode(PDO::FETCH_OBJ); 

     if($stmt->execute()){ 
       return (array) $stmt->fetchObject(); 
     } else { 
      return false; 
     } 
    } 

    catch(PDOException $e) { 
     $_messages[] = $e->getMessage(); 
    } 
} 

而且使用這樣的

$my_array = getObject($your_query); 

if(!empty($my_array['mon_m'])){ 
    echo $my_array['mon_m']; 
}