我試圖簡化開關語句,它需要大量空間和時間來編寫。在代碼中,你會明白的。如果沒有,我會稍後解釋。簡化開關語句(Objective-C)
// When row is selected
- (void)pickerView:(UIPickerView *)pickerTimer didSelectRow:(NSInteger)row inComponent:(NSInteger)component {
switch (row) {
case 0:
NSLog(@"It obviously worked.0");
break;
case 1:
NSLog(@"It obviously worked.1");
break;
case 2:
NSLog(@"It obviously worked.2");
break;
case 3:
NSLog(@"It obviously worked.3");
break;
case 4:
NSLog(@"It obviously worked.4");
break;
case 5:
NSLog(@"It obviously worked.5");
break;
case 6:
NSLog(@"It obviously worked.6");
break;
default:
NSLog(@"It did kindof work.NIL");
break;
}
}
有什麼辦法可以簡化這個嗎?只是這樣做,
NSLog(@"It did work! %@", row);
爲了記錄,我試過了,並沒有奏效。
哈,我是這樣的noob .. 是否有格式說明符等地方的任何概述? 謝謝:) – Emil 2010-02-09 19:37:36
只需在C printf上進行搜索,它不會列出%@,但它包含了其他所有內容。 – 2010-02-09 19:52:46
@Emil:此鏈接包含Core Foundation支持的所有格式說明符:http://developer.apple.com/mac/library/documentation/cocoa/Conceptual/Strings/Articles/formatSpecifiers.html#//apple_ref/doc/uid/TP40004265。 – dreamlax 2010-02-09 23:49:18