float []區別

Question

我在想什麼是找到兩個浮點數組之間差異絕對值的最有效方法？

它是以下幾點：

private float absDifference(float[] vector1, float[] vector2) { 
    float difference=0; 
    int len=Math.max(vector1.length, vector2.length); 
    for(int n=0;n<len;n++){ 
     float diff=0; 
     if(n<vector1.length){ 
      diff+=vector1[n]; 
     } 
     if(n<vector2.length){ 
      diff-=vector2[n]; 
     } 
     difference+=Math.abs(diff); 
    } 
    return difference; 
} 

Answer 1

private float absDifference(float[] vector1, float[] vector2) { 
    float difference=0; 
    int len=Math.min(vector1.length, vector2.length); 
    for(int n=0;n<len;n++){ 
      diff+=vector1[n]-vector2[n]; 
     difference+=Math.abs(vector1[n]-vector2[n]); 
    } 
    if(vector1.length > vector2.length){ 
     for(;n<vector1.length;n++){ 
      difference+=Math.abs(vector1[n]); 
     } 
    }else{ 
     for(;n<vector2.length;n++){ 
      difference+=Math.abs(vector2[n]); 
     } 
    } 
    return difference; 
} 

這種方式有沒有重複的邊界檢查第一循環中的時間越長陣列的其餘部分分開處理後