2012-01-03 103 views
0

我想在我的網站自動幻燈:Test Site自動化動畫/點擊的JavaScript

我發現這個真棒jQuery的模板在線:http://tympanus.net/codrops/2011/08/...ge-navigation/。我修改了html/css,並讓它看起來像我想要的,但現在需要JavaScript幫助!

當您單擊箭頭時,幻燈片顯示當前正在進行,但我想知道是否有自動化點擊功能的方法,以便在加載網頁時自動啓動幻燈片動畫。我仍然希望用戶能夠用箭頭控制幻燈片。我還希望當幻燈片到達最後一張圖像時,它會返回到第一張圖像。

(function($){ 
$.fn.portfolio = function(options) { 
    var d = { 
      image: { 
       width: 760, 
       height: 507, 
       margin: 10 
      }, 
      path: { 
       width: 10, 
       height: 10, 
       marginTop: 5, 
       marginLeft: 5 
      }, 
      animationSpeed: 400 
    }; // default settings 

    var s = $.extend({}, d, options); 

    return this.each(function(){ 
     var $t = $(this), 
      plugin = { 
       init: function(){ 
        this.set.position(); 
        this.paths.draw(); 
        this.paths.go(); 
        this.animate.item(); 
       }, 
       set: { 
        position: function(){ 
         $t.find('.item').each(function(i){ 
          var t = $(this); 
          t.css({ left: (s.image.width+s.image.margin)*i+'px' }); 
          t.find('div').each(function(j){ 
           var t = $(this); 
           t.css({ top: (s.image.height+s.image.margin)*j+'px' }); 
          }); 
         }); 
        } 
       }, 
       paths: { 
        draw: function(){ 
         $t.append($('<div />').addClass('paths')); 
         var path = $t.find('.paths'), 
          items = $t.find('.item'); 
         items.each(function(i){ 
          var t = $(this), div = t.find('div'); 
          path.append($('<div />').addClass('path'+i).css({ 
            width: s.path.width+'px', 
            left: (s.path.width+s.path.marginLeft)*i+'px' 
           }) 
          ); 
          div.each(function(j){ 
           $('<a />').attr({ href: '#', rel: j }).css({ 
            width: s.path.width+'px', 
            height: s.path.height+'px', 
            top: (s.path.height+s.path.marginTop)*j+'px' 
           }).appendTo(path.find('.path'+i)) 
          }); 
         }); 
         path.find('.path0').find('a').eq(0).addClass('active'); 
        }, 
        go: function(){ 
         $t.find('.paths').find('a').click(function(){ 
          var t = $(this), all = $t.find('.paths').find('a'), column = t.parent('div').attr('class').split('path')[1], row = t.attr('rel'), 
           inside = $t.find('.inside'), 
           top = row*(s.image.height+s.image.margin), 
           left = column*(s.image.width+s.image.margin); 
          inside.animate({ 
           top: -top+'px', 
           left: -left+'px' 
          }, s.animationSpeed, function(){ 
           plugin.position.get(inside); 
          }); 
          return false; 
         }); 
        }, 
        classes: function(column, row){ 
         var anchors = $t.find('.paths').find('a'), anchor = anchors.filter(function(){ 
          var t = $(this), 
           col = t.parent('div').attr('class').split('path')[1], 
           r = t.attr('rel'); 
          return col == column && r == row; 
         }); 
         anchors.removeClass('active'); 
         anchor.addClass('active'); 
        } 
       }, 
       animate: { 
        item: function(){ 
         var down = { top: '-='+(s.image.height+s.image.margin)+'px' }, 
          up = { top: '+='+(s.image.height+s.image.margin)+'px' }, 
          next = { top: 0, left: '-='+(s.image.width+s.image.margin)+'px' }, 
          prev = { top: 0, left: '+='+(s.image.width+s.image.margin)+'px' } 
         plugin.animate.img('.down', down, 40); 
         plugin.animate.img('.up', up, 38); 
         plugin.animate.img('.next', next, 39); 
         plugin.animate.img('.prev', prev, 37); 
        }, 
        img: function(element, object, key){ 
         var inside = $t.find('.inside'), type = $.browser.mozilla ? 'keypress' : 'keydown'; 
         $(element).click(function(){ 
          var t = $(this); 
          if (!t.hasClass('active')){ 
           inside.animate(object, s.animationSpeed, function(){ 
            plugin.position.get(inside); 
            t.removeClass('active'); 
           }); 
          } 
          t.addClass('active'); 
          return false; 
         }); 
         $(document).bind(type, function(e) { 
          var code = e.keyCode ? e.keyCode : e.which; 
          if(code == key && $(element).is(':visible')) { 
           if (!inside.is(':animated')) { 
            inside.animate(object, s.animationSpeed, function(){ 
             plugin.position.get(inside); 
            }); 
           } 
          } 
          return false; 
         }); 

        } 
       }, 
       position: { 
        get: function(element){ 
         var top = element.position().top, 
          left = element.position().left; 
         plugin.position.check(top, left); 
        }, 
        check: function(top, left){ 
         top = ($.browser.msie && parseInt($.browser.version) == 8 && top != 0) ? top-1 : top; 
         var items = $t.find('.item'), 
          size_left = items.length-1, 
          max_left = -size_left*(s.image.width+s.image.margin), 
          column = left*size_left/max_left, 
          current = items.filter(function(){ 
           return parseInt($(this).css('left')) == -left; 
          }), 
          size_top = current.find('div').length-1, 
          max_top = -size_top*(s.image.height+s.image.margin), 
          row = top*size_top/max_top, 
          arrows = $t.find('.arrows'), 
          up = arrows.find('.up'), down = arrows.find('.down'), 
          next = arrows.find('.next'), prev = arrows.find('.prev'); 
         if (left==max_left){ next.hide(); } else { next.show(); } 
         if (left<0) { prev.show(); } else { prev.hide(); } 
         if (top==max_top){ down.hide(); } else { down.show(); } 
         if (top<0) { up.show(); } else { up.hide(); } 
         plugin.paths.classes(column, row); 
        } 
       } 
      } 
     plugin.init(); 
    }); 
};}(jQuery)); 

回答

0

只需製作一個計時器,即調用$(".next").click();即可使幻燈片繼續前進。

+0

一旦它到達第五張圖像,我該如何讓它返回到開頭? – user1126996 2012-01-05 03:37:07