不需要自動創建的續集的id屬性

Question

let data = require('./../../config/db') 
let connection = data.connection 
let sequelize = data.sequelize 
let sql = function(){ 
    let clubMembers = connection.define('club_members',{ 
      position:{ 
       type :sequelize.ENUM('President','Treasurer') , 
       allowNull : false 
      } 
     }, 
     { 
      classMethods : { 
       associate : function(models){ 
        let clubMembers = models.club_members 
        let club = models.club 
        let student = models.student 
        club.hasMany(clubMembers,{ 
         foreignKey : "club_id" 
        }) 
        student.hasMany(clubMembers,{ 
         foreignKey : "student_id" 
        }) 
       } 
      } 
     } 
    ); 
    return clubMembers; 
} 
module.exports = sql; 

我不需要id屬性在此表中但自動創建它。兩個外鍵的組合應該被視爲主鍵，即組合主鍵。

Answer 1

您應該使用belongsToMany在associate功能

associate: function(models){ 
    models.club.belongsToMany(models.student, { through: models.club_members, foreignKey: 'club_id' }); 
    models.student.belongsToMany(models.club, { through: models.club_members, foreignKey: 'student_id' }); 
} 

這將創建club_members表由club_id和student_id複合主鍵，沒有默認id列。