的Oracle SQL：添加行選擇結果

Question

說我有一個列的表格：id, group_id, type, val
從選擇一些示例數據：
1, 1, 'budget', 100
2, 1, 'budget adjustment', 10
3, 2, 'budget', 500
4, 2, 'budget adjustment', 30

我想要的結果看起來像
1, 1, 'budget', 100
2, 1, 'budget adjustment', 10
5, 1, 'budget total', 110
3, 2, 'budget', 500
4, 2, 'budget adjustment', 30
6, 2, 'budget total', 530

請指教，
感謝。

Answer 1

由於@Serpiton建議，看來你真的需要的功能，是小計添加到您的能力結果集，這表明rollup是您需要的。用法是這樣的：

SELECT id, 
     group_id, 
     coalesce(type, 'budget total') as type, 
     sum(val) as val 
FROM  your_table 
GROUP BY ROLLUP (group_id), id, type 

Answer 2

這將得到您需要的兩個添加行，但不是您想要的ID和類型的值。

甲骨文例子：http://docs.oracle.com/cd/B19306_01/server.102/b14223/aggreg.htm

Select id, group_id, type as myType, sum(val) as sumVal 
FROM Table name 
Group by Grouping sets ((id, group_id, type, val), (group_ID)) 

Answer 3

可以使用UNION ALL更行添加到原來的選擇。

select group_id,type,val from tableA 
union all 
select group_id, 'budget total' as type,sum(val) as val from tableA group by group_id,type 

要顯示正確的順序和id，你可以使用嵌套選擇

select rownum, group_id,type,val from (select group_id,type,val from tableA 
union all 
select group_id, 'budget total' as type,sum(val) as val from tableA group by group_id,type) order by group_id asc 

Answer 4

with foo as 
(select 1 group_id, 'budget' type, 100 val 
    from dual 
    union 
    select 1, 'budget adjustment', 10 
    from dual 
    union 
    select 2, 'budget', 500 
    from dual 
    union 
    select 2, 'budget adjustment', 30 
    from dual) 
SELECT rank() over(order by type, group_id) rk, 
     group_id, 
     nvl(type, 'budget total') as type, 
     sum(val) as val 
    FROM foo 

group by Grouping sets((group_id, type, val),(group_id)) 

它就是xQbert後的延續，有ID值！