在陣列分組連續日期一起在PHP

我已經在陣列中的下面的日期（日期不會總是這些日期）在陣列分組連續日期一起在PHP

[0] 2012-10-18 
[1] 2012-10-19 
[2] 2012-10-20 
[3] 2012-10-23 
[4] 2012-10-24 
[5] 2012-10-29 
[6] 2012-10-30

欲組連續日期在一起，以便輸出爲：

2012-10-18 to 2012-10-20 
2012-10-23 to 2012-10-24 
2012-10-29 to 2012-10-30

我該如何在PHP中做到這一點？

謝謝！

來源

2012-10-19 Franco

檢查此問題http://stackoverflow.com/questions/8461543/check-for-consecutive-dates-within-a-set-and-return-as-range – Sibu

這段代碼將連續日期分組在一起，並理解夏令時。數字

陣列

$dates = array 
(
strtotime('2012-10-01'), 

strtotime('2012-10-03'), 
strtotime('2012-10-04'), 
strtotime('2012-10-05'), 
strtotime('2012-10-06'), 
strtotime('2012-10-07'), 

strtotime('2012-10-10'), 
strtotime('2012-10-11'), 
strtotime('2012-10-12'), 
strtotime('2012-10-13'), 
strtotime('2012-10-14'), 
strtotime('2012-10-15'), 
strtotime('2012-10-16'), 
strtotime('2012-10-17'), 
strtotime('2012-10-18'), 
strtotime('2012-10-19'), 
strtotime('2012-10-20'), 

strtotime('2012-10-23'), 
strtotime('2012-10-24'), 
strtotime('2012-10-25'), 
strtotime('2012-10-26'), 
strtotime('2012-10-29'), 
strtotime('2012-10-30'), 
strtotime('2012-10-31'), 
strtotime('2012-11-01'), 
strtotime('2012-11-02'), 

strtotime('2012-11-04') 
);

代碼：

$conseq = array(); 
$ii = 0; 
$max = count($dates); 

for($i = 0; $i < count($dates); $i++) { 
    $conseq[$ii][] = date('Y-m-d',$dates[$i]); 

    if($i + 1 < $max) { 
     $dif = $dates[$i + 1] - $dates[$i]; 
     if($dif >= 90000) { 
      $ii++; 
     } 
    } 
}

輸出：

array 
    0 => 
    array 
     0 => string '2012-10-01' (length=10) 
    1 => 
    array 
     0 => string '2012-10-03' (length=10) 
     1 => string '2012-10-04' (length=10) 
     2 => string '2012-10-05' (length=10) 
     3 => string '2012-10-06' (length=10) 
     4 => string '2012-10-07' (length=10) 
    2 => 
    array 
     0 => string '2012-10-10' (length=10) 
     1 => string '2012-10-11' (length=10) 
     2 => string '2012-10-12' (length=10) 
     3 => string '2012-10-13' (length=10) 
     4 => string '2012-10-14' (length=10) 
     5 => string '2012-10-15' (length=10) 
     6 => string '2012-10-16' (length=10) 
     7 => string '2012-10-17' (length=10) 
     8 => string '2012-10-18' (length=10) 
     9 => string '2012-10-19' (length=10) 
     10 => string '2012-10-20' (length=10) 
    3 => 
    array 
     0 => string '2012-10-23' (length=10) 
     1 => string '2012-10-24' (length=10) 
     2 => string '2012-10-25' (length=10) 
     3 => string '2012-10-26' (length=10) 
    4 => 
    array 
     0 => string '2012-10-29' (length=10) 
     1 => string '2012-10-30' (length=10) 
     2 => string '2012-10-31' (length=10) 
     3 => string '2012-11-01' (length=10) 
     4 => string '2012-11-02' (length=10) 
    5 => 
    array 
     0 => string '2012-11-04' (length=10)

來源

2012-10-19 04:50:09 Tivie

$selectedDays = array(2012-10-18, 
2012-10-19, 
2012-10-20, 
2012-10-23, 
2012-10-24, 
2012-10-29, 
2012-10-30) 

$intervals = array(); 
        $i=0; 
        $j=1; 
        $diff=86400; 
        $period = $diff; 
        $nrInterval=0; 
        $intervals[$nrInterval]['start'] = $selectedDays[$i]; 
        $intervals[$nrInterval]['end'] = $selectedDays[$i]; 
        while($j<count($selectedDays)){ 
         if(strtotime($selectedDays[$j])-strtotime($selectedDays[$i]) == $period){ 
          $intervals[$nrInterval]['end'] = $selectedDays[$j]; 
          $j++; 
          $period+=$diff; 
         } 
         else{ 
          $i=$j; 
          $j++; 
          $nrInterval++; 
          $intervals[$nrInterval]['start'] = $selectedDays[$i]; 
          $intervals[$nrInterval]['end'] = $selectedDays[$i]; 
          $period = $diff; 
         } 
        } 


//print_r($intervals); will output 
array(
'0'=>array('start' => '2012-10-18','end' => '2012-10-20')) 
. 
. 
. 
.etc 
)

來源

2013-09-26 11:06:55

在陣列分組連續日期一起在PHP

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