Question

我想問題都是這樣說的。我的查詢結果將成爲一個匹配條件的行。我想從每個表列中獲取每個數據並將其放入一個變量中。

$getinfo = "select 
        user_firstname, 
        user_middlename, 
        user_lastname 
       from tempuserinfo 
      where user_email ='$ead' 
       and activation_code='$eac'"; 

$query = mysql_query($getinfo, $db); 
if(!$query) { 
    echo'something went wrong.'; 
} else { 
    //put them into variables 
    $firstname = mysql_fetch_object($query, 'user_firstname'); 
    $middlename = mysql_fetch_object($query, 'user_middlename'); 
    $lastname = mysql_fetch_object($query, 'user_lastname'); 
} 

Answer 1

，你可以通過他們像環這個：

$getinfo = "select user_firstname, user_middlename, user_lastname from tempuserinfo where user_email ='$ead' and activation_code='$eac'"; 
$query = mysql_query($getinfo, $db); 

while ($row = mysql_fetch_array($query)) { 
    $firstname = $row['user_firstname']; 
    $lastname = $row['user_lastname']; 
} 

如果你只得到一個行回來（請確保您添加了限制你的SQL語句），那麼你可以使用這樣的事情：

$getinfo = "select user_firstname, user_middlename, user_lastname from tempuserinfo where user_email ='$ead' and activation_code='$eac'"; 
$query = mysql_query($getinfo, $db); 

$row = mysql_fetch_array($query); 

$firstname = $row['user_firstname']; 
$lastname = $row['user_lastname']; 

Answer 2

這應該工作：

$result = mysql_fetch_object($query); 
$firstname = $result->user_firstname; 
$middlename = $result->user_middlename; 
$lastname = $result->user_lastname; 

但是： 使用的MySQLi或者如果您收到多個結果PDO sintead mysql的模塊已經過時

Answer 3

$dsn = 'mysql:dbname=testdb;host=127.0.0.1'; 
    $user = 'dbuser'; 
    $password = 'dbpass'; 

    try { 
     $dbh = new PDO($dsn, $user, $password); 
    } catch (PDOException $e) { 
     echo 'Connection failed: ' . $e->getMessage(); 
    } 
    try { 
     $sth = $dbh->prepare("select user_firstname, user_middlename, user_lastname from tempuserinfo where user_email = ? and activation_code=?"); 
     $sth->execute(array($ead,$eac)); 
     $row = $sth->fetch(PDO::FETCH_BOTH); 
     $user_firstname = $row['user_firstname']; 
     $user_middlename = $row['user_middlename']; 
     $user_lastname = $row['user_lastname']; 
} catch (PDOException $e) { 
     echo 'Database operation failed: ' . $e->getMessage(); 
    } 

真的，學會使用PDO，因爲它就像使用mysql_ *一樣簡單，但更安全，更好。

Answer 4

mysql_ *函數已被棄用。在最新版本的PHP中推薦的文檔中，他們將使用mysqli_ *或PDO。

下面是使用mysqli的爲您的問題腳本：

$mysqli = new mysqli("localhost", "root_user", "root_password", "database"); 
if (mysqli_connect_errno()) { 
    printf("Connect failed: %s\n", mysqli_connect_error()); 
    exit(); 
} 

$getinfo = "select 
        user_firstname, 
        user_middlename, 
        user_lastname 
       from tempuserinfo 
      where user_email ='$ead' 
       and activation_code='$eac'"; 



if ($result = $mysqli->query($getinfo)) {  
    while ($row = $result->fetch_object()) { 
     $firstname = $row->user_firstname; 
     $middlename = $row->user_middlename; 
     $lastname =$row->user_lastname; 
    } 
    $result->close(); 
} 
else 
{ 
    echo'something went wrong.'; 
} 

Answer 5

與mysqli的一個例子，MySQL作爲這種過時

$sql = "select user_firstname, user_middlename, user_lastname from tempuserinfo where user_email ='$ead' and activation_code='$eac'"; 

$query = mysqli_query($conn, $sql); 
while($rs = mysqli_fetch_assoc($query)){ 
    $user_firstname = $rs['user_firstname']; 
    $user_middlename = $rs['user_middlename']; 
    $user_lastname = $rs['user_lastname']; 
} 

，如果你想擁有的所有字段，以便稍後徵詢他們的意見，將它們添加到陣列中

$i=0; 
while($rs = mysqli_fetch_assoc($query)){ 
    $data[$i] = array('user_firstname'=>$rs['user_firstname'], 'user_middlename'=>$rs['user_middlename'], 'user_lastname'=> $rs['user_lastname']); 

    $i++; 
} 

print_r($data);