如何使用C分配char *值到char使用C

Question

我有變量char * amount;和char t_amount; 我想將金額分配給t_amount。

char * amount = "sdf"; 
char t_amount = amount; 
printf("%s t_amount \n", t_amount); 
// I am expecting : sdf t_amount 

當我打印，發生分割錯誤，所以我如何解決這個問題？ 希望你們能幫助我。

Answer 1

變量amount是一個指針，所以當char t_amount = amount;你實際上是分配指針的地址給你t_amount變量，因此段錯誤 如果t_amount是char *你可以做那項任務沒有任何錯誤。

Answer 2

char * amount = "sdf"; 
char t_amount = amount; 
printf("%s t_amount \n", t_amount); 

amount is a pointer you can not assign that kind of address to a variable. its an error. 
when you declare char t_amount = amount, you assign a string to a char because an address is a string.