從頻率詞典獲取字數和平均長度

Question

如果我有一個頻率字典，其中包含文本中的詞作爲鍵和它們在文本中出現的次數作爲值。我怎樣才能得到字數和平均長度，確保考慮到多次出現的單詞？現在我所擁有的僅僅是列出鍵（因爲它們是單詞），然後使用len（）進行單詞計數。

wordcount=len(list(freq.keys())) 
report["count:"]=wordcount 
#for average length: 
avg=list(freq.keys()) 
average=sum(map(len,avg))/len(avg) 
report["avglen"]=average 

Answer 1

使用sum功能和dict.values()：

freq = { 'test' : 10, 'rep' : 100 } 
wordcount = sum(freq.values()) 
average = sum(len(w) * c for w, c in freq.items())/wordcount 
print(wordcount, average) 

Answer 2

number_of_words = int(raw_input("Enter the number of words. ")) 

word_dict = {} 

for i in range(number_of_words): 
    word = raw_input("Enter word. ") 
    if word in word_dict: 
     word_dict[word] += 1 
    else: 
     word_dict[word] = 1 

print word_dict 

print sum([len(word)*word_dict[word] for word in word_dict])/number_of_words 

一個非常類似的問題：https://stackoverflow.com/questions/20143947/word-frequency-counter-python/20145320#20145320