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說我有這個如何檢查矢量中的兩個元素是否按順序排列?
vector<int>SequentialByOne{1, 2, 3, 4, 5} //would like to search each element
//in the vector and if it is sequential a boolean value returns true
vector<int>notSequential{1, 6, 5, 8, 9} // This would return false
vector<int>notSequentialButOrdered{1, 3, 6, 9, 20} // This would return false
// So far I can get it to return true if the next number
// is bigger than the previous but can't figure out
// how to check that the next number is only one bigger.
這是一個撲克手電梯我工作的學校項目。我有一個有序的5個數字的矢量,現在我需要搜索該矢量以查找它們是否按照精確的順序+1。
這是我到目前爲止
sort(hand.begin(), hand.end()); // This is the vector name
int a;
{
for(int i = 0; i < 4; i++)
{
if(hand[i] < hand[i + 1] - 1)
a++;
}
}
bool has_straight
{
if(a == 5)
return true;
}
不太清楚是什麼問題。如果你想檢查平等而不是不平等,那麼就做,如果(手[I] =手[I + 1] + 1)'而不是'如果(手[I] <手[I + 1] - 1)' – user463035818
檢查'hand [i + 1] - hand [i] == 1'?或者說,檢查'hand [i + 1] - hand [i]!= 1',如果是true,則返回false。 –
你現在的代碼有什麼問題?如果您希望某人查看您的代碼,請訪問:https://codereview.stackexchange.com/ – Lanting