postgresql按大小排列列表和排序表

Question

是否有一種簡單的方法可以列出PostgreSQL數據庫中的所有表並按大小排序？

僞代碼

SELECT * FROM tables 
ORDER by tables.size 

我使用PostgreSQL9.3.2。

Answer 1

select table_name, pg_relation_size(quote_ident(table_name)) 
from information_schema.tables 
where table_schema = 'public' 
order by 2 

這說明你的模式，如果你有多個模式public所有表的大小，您可能需要使用：

select table_schema, table_name, pg_relation_size('"'||table_schema||'"."'||table_name||'"') 
from information_schema.tables 
order by 3 

SQLFiddle例如：http://sqlfiddle.com/#!15/13157/3

所有對象的列表尺寸功能：
https://www.postgresql.org/docs/current/static/functions-admin.html#FUNCTIONS-ADMIN-DBSIZE

Answer 2

這將s你的架構名稱，表名，大小漂亮和大小（需要排序）。

SELECT 
    schema_name, 
    relname, 
    pg_size_pretty(table_size) AS size, 
    table_size 

FROM (
     SELECT 
     pg_catalog.pg_namespace.nspname   AS schema_name, 
     relname, 
     pg_relation_size(pg_catalog.pg_class.oid) AS table_size 

     FROM pg_catalog.pg_class 
     JOIN pg_catalog.pg_namespace ON relnamespace = pg_catalog.pg_namespace.oid 
    ) t 
WHERE schema_name NOT LIKE 'pg_%' 
ORDER BY table_size DESC; 

我建立這個基礎上從這裏list of schema with sizes (relative and absolute) in a PostgreSQL database

Answer 3

select table_name,n_live_tup, pg_size_pretty(pg_relation_size(table_name)) 
from information_schema.tables 
inner join pg_stat_user_tables on table_name=relname 
where table_schema = 'public' 
order by 2 desc 

的解決方案，另一種選擇

Answer 4

select uv.a tablename, pg_size_pretty(uv.b) sizepretty from 
(select tb.tablename a, pg_table_size('schemaname.'||tb.tablename::text) b from pg_tables tb where tb.schemaname ilike 'schemaname' order by 2 desc) uv 

Answer 5

SELECT 
    relname as "Table", 
    pg_size_pretty(pg_total_relation_size(relid)) As "Size", 
    pg_size_pretty(pg_total_relation_size(relid) - pg_relation_size(relid)) as "External Size" 
    FROM pg_catalog.pg_statio_user_tables ORDER BY pg_total_relation_size(relid) DESC; 

如果您使用的是命令 - 從這裏https://wiki-bsse.ethz.ch/display/ITDOC/Check+size+of+tables+and+objects+in+PostgreSQL+database