長度 '的char * numberlist []' C和C++

Question

試圖找出如何讓焦項目總數* numberlist []在C和C++，下面是代碼：

const char* list_of_filename[] = {"One","Two","Three","Four","Five"}; 

Answer 1

查找數組中的元素的數量的標準習慣用法

int num_items = sizeof(list_of_filename)/sizeof(list_of_filename[0]); 

Answer 2

如何：

sizeof(list_of_filename)/sizeof(char*) 

或者更一般地：

sizeof(list_of_filename)/sizeof(list_of_filename[0])