列表供應商和最低價產品SQL

Question

我試圖加入2個表並創建一個返回產品最低價值的新字段。我嘗試了很多變化，似乎無法讓它工作。

SELECT DISTINCT VENDOR.*, PRODUCT.P_PRICE, PRODUCT.LOWEST_PRICE AS MIN(PRODUCT.P_PRICE) 
FROM PRODUCT 
INNER JOIN VENDOR 
ON VENDOR.V_CODE = PRODUCT.V_CODE 
ORDER BY VENDOR.V_NAME 

Answer 1

你可以使用這個，這將從最低價格供應商的產品訂購

SELECT VENDOR.V_NAME, MIN(PRODUCT.P_PRICE) AS LOWEST_PRICE 
FROM VENDOR 
INNER JOIN PRODUCT 
ON VENDOR.V_CODE = PRODUCT.V_CODE 
GROUP BY VENDOR.V_NAME 
ORDER BY LOWEST_PRICE 

SQL FIDDLE： - http://sqlfiddle.com/#!3/467c8/2

Answer 2

如果你是供應商，使用GROUP BY和分鐘尋找最低價格：

SELECT VENDOR.V_NAME, MIN(PRODUCT.P_PRICE) AS LOWEST_PRICE 
FROM PRODUCT 
INNER JOIN VENDOR 
ON VENDOR.V_CODE = PRODUCT.V_CODE 
GROUP BY VENDOR.V_NAME 
ORDER BY VENDOR.V_NAME 

Answer 3

不知道你的架構是如何定義試試這個：

SELECT 
    VENDOR.V_NAME, 
    PRODUCT.P_PRICE AS [VENDOR PRICE], 
    MIN(PRODUCT.P_PRICE) AS [LOWEST PRICE] 
FROM 
    PRODUCT 
    INNER JOIN VENDOR ON VENDOR.V_CODE = PRODUCT.V_CODE 
GROUP BY 
    VENDOR.V_NAME,PRODUCT.P_PRICE 
ORDER BY 
    VENDOR.V_NAME 

Answer 4

如果你想每個供應商的價格最低的產品，我會建議使用窗口功能：

select pv.* 
from (select v.v_name, p.p_name, p.p_price 
      row_number() over (partition by p.v_code order by p.p_price asc) as seqnum 
     from vendor v join 
      product p 
      on v.v_code = p.v_code 
    ) pv 
where seqnum = 1