圖表barh matplotlib - 重疊條

Question

我是matplotlib的新用戶，我有一個圖表barh問題：重疊條。 當繪製圖表時，條形圖重疊，我沒有找到原因。在我看來，問題在於重新調整圖表的大小。我重新調整它的大小，因爲將來我會插入標題，圖例和x，y描述。我嘗試一些解決方案，但我有一個解決方案！ 這是我的代碼：

import matplotlib.pyplot as plt 
    import matplotlib.font_manager as fm 
    from matplotlib.colors import LightSource 
    from matplotlib.artist import Artist 
    import numpy as np 
    from decimal import * 
    import datetime 
    #Size 
    width = 360 
    height = 240 
    dpi = 80.0 
    colors = ['#be1e2d', 
      '#666699', 
      '#92d5ea', 
      '#ee8310', 
      '#8d10ee', 
      '#5a3b16', 
      '#26a4ed', 
      '#f45a90', 
      '#e9e744'] 
    #Data 
    columns = ['2005','2006'] 
    data = [[2.6,3.5],[2, 1.5]] 
    linewidth = 1 
    N = len(columns) 

    ind = np.arange(N) 
    #Re-Size 
    rdata = len(data) if columns is None else len(columns) 
    heightColumn = height*1.0/(rdata)/(len(columns)) 
    heightColumn = heightColumn/dpi 
    fig = plt.figure(1, figsize=(width/dpi,height/dpi),facecolor='w') 
    ax = fig.add_axes([0.2, 0.3, 0.6, 0.5]) 
    #Draw 
    tupleRects =() 
    idxColor = 0 
    valPositionCol = ind 
    for dat in data: 
     rects = plt.barh(valPositionCol, dat, heightColumn, color=colors[idxColor], alpha=0.8, 
         linewidth=linewidth) 
     valPositionCol=valPositionCol+heightColumn 
     idxColor += 1 
     if idxColor==9: 
      idxColor = 0 
     tupleRects += (rects,) 
    plt.show() 

THANKS

---

的代碼是相同的，但我改變數據（列[]ë數據[]）：

import matplotlib.pyplot as plt 
import matplotlib.font_manager as fm 


from matplotlib.colors import LightSource 
import numpy as np 
from decimal import * 
import datetime 
#Size 
width = 360 
height = 240 
dpi = 80.0 
colors = ['#be1e2d', 
      '#666699', 
      '#92d5ea', 
      '#ee8310', 
      '#8d10ee', 
      '#5a3b16', 
      '#26a4ed', 
      '#f45a90', 
      '#e9e744'] 
#Data 
columns = ['2005','2006'] 
data = [[1.5, 1.5], [1.5,1.5], [1.5,1.5]] 
linewidth = 1 
N = len(columns) 


ind = np.arange(N) 
#Re-Size 
height_of_group = .9 


heightColumn = height_of_group/(len(columns)) 
fig = plt.figure(1, figsize=(width/dpi,height/dpi),facecolor='w') 
ax = fig.add_axes([0.2, 0.3, 0.6, 0.5]) 
#Draw 


tupleRects =() 
idxColor = 0 
valPositionCol = ind 
for dat in data: 
    rects = plt.barh(valPositionCol, dat, heightColumn, color=colors[idxColor], alpha=0.8, 
        linewidth=linewidth) 
    valPositionCol=valPositionCol+heightColumn 
    idxColor += 1 
    if idxColor==9: 
     idxColor = 0 
    tupleRects += (rects,) 
plt.show() 

的問題是我有可變數據，我必須找到一個穩定的算法。

Answer 1

我想你是錯誤理解身高的意思（doc）。單位是軸單位，而不是像素。

heightColumn = height*1.0/(rdata)/(len(columns)) 
heightColumn = heightColumn/dpi 

到

height_of_group = .9 
heightColumn = height_of_group/(len(data)) 
#heightColumn = heightColumn/dpi 

將獲得非重疊的酒吧只是一個位的組之間的額外空間。只要height_of_group大於或小於1，您就可以調整組之間的空間。