ORA-00904：在這種情況下無效的標識

Question

這裏是我的解決方案，我想顯示所有的信息在3個表中的薪水，當我把薪水放在最後，不管我嘗試了什麼，我仍然錯了。有人幫我修復。我不知道如何顯示只有15行的工資。

SELECT Bld.id,C.code,M.FIRST_NAME,M.LAST_NAME,Bld.Address,M.ADDRESS,D.DOB,S.SALARY 
    from HW1_PERSON M 
    inner join HW1_BUILDING Bld 
    ON M.id = Bld.id 
    INNER JOIN HW1_PERSON M 
    ON Bld.id = M.id 
    INNER JOIN HW1_PERSON M 
    ON M.id = Bld.id 
    Inner JOIN HW1_BUILDING Bld 
    ON Bld.id = M.id 
    INNER JOIN HW1_BUILDING C 
    ON M.id = C.id 
    INNER JOIN HW1_PERSON D 
    ON M.id = D.id 
    UNION ALL 
    SELECT Bld.id,C.code,M.FIRST_NAME,M.LAST_NAME,Bld.Address,M.ADDRESS,D.DOB,S.SALARY FROM HW1_STAFF S 
    where S.SALARY = NULL 
    ; 

---

下面是表

CREATE TABLE HW1_PERSON (
    ID INT NOT NULL, 
    FIRST_NAME VARCHAR(32) NOT NULL, 
    LAST_NAME VARCHAR(32) NOT NULL, 
    DOB DATE, 
    ADDRESS VARCHAR2(32), 
    CONSTRAINT PK_HW1_PERSON_ID PRIMARY KEY (ID)); 

CREATE TABLE HW1_STAFF (
    SALARY DOUBLE PRECISION NOT NULL, 
    START_DATE DATE NOT NULL, 
    END_DATE DATE DEFAULT NULL, 
    EMP_NUM VARCHAR(5) NOT NULL UNIQUE, 
    PERSON_ID INT NOT NULL, 
    CONSTRAINT PK_HW1_STAFF PRIMARY KEY (PERSON_ID), 
    CONSTRAINT FK_STAFF_PERSON FOREIGN KEY(PERSON_ID) REFERENCES HW1_PERSON(ID)); 

CREATE TABLE HW1_BUILDING (
    ID INT NOT NULL, 
    CODE VARCHAR2(5) NOT NULL UNIQUE, 
    NAME VARCHAR2(32) NOT NULL, 
    ADDRESS VARCHAR2(32), 
    MANAGER_ID INT, 
    CONSTRAINT PK_HW1_BUILDING PRIMARY KEY (ID), 
    CONSTRAINT FK_BUILDING_STAFF FOREIGN KEY(MANAGER_ID) REFERENCES HW1_STAFF(PERSON_ID)); 

CREATE TABLE HW1_EMPLOYEE (
    ID INT NOT NULL, 
    PERSON_ID INT, 
    BUILDING_ID INT, 
    CONSTRAINT PK_HW1_EMPLOYEE PRIMARY KEY (PERSON_ID,BUILDING_ID), 
    CONSTRAINT FK_STAFF_ID FOREIGN KEY(PERSON_ID) REFERENCES HW1_STAFF(PERSON_ID), 
    CONSTRAINT FK_BUILDING_ID FOREIGN KEY(BUILDING_ID) REFERENCES HW1_BUILDING(ID)); 

---

資料實例

INSERT INTO hw1_person (id, first_name, last_name, dob, address) VALUES (1, 'fname11', 'lname11', to_date('7/27/1990', 'MM/DD/YYYY'), '527 15th Av CT'); 
INSERT INTO hw1_person (id, first_name, last_name, dob, address) VALUES (2, 'fname12', 'lname12', to_date('12/5/1966', 'MM/DD/YYYY'), '254 11th St CT'); 


INSERT INTO hw1_staff (person_id, emp_num, start_date, end_date, salary) VALUES (1, 'WZIAE', to_date('7/1/1965', 'MM/DD/YYYY'), null,70000); 
INSERT INTO hw1_staff (person_id, emp_num, start_date, end_date, salary) VALUES (2, 'EWEMU', to_date('11/18/1980', 'MM/DD/YYYY'), to_date('12/26/1970', 'MM/DD/YYYY'),80000); 
INSERT INTO hw1_staff (person_id, emp_num, start_date, end_date, salary) VALUES (25, '00001', to_date('5/21/1994', 'MM/DD/YYYY'), null,0); 
INSERT INTO hw1_staff (person_id, emp_num, start_date, end_date, salary) VALUES (26, '00002', to_date('7/19/1985', 'MM/DD/YYYY'), null,0); 

Answer 1

SELECT Bld.id,C.code,M.FIRST_NAME,M.LAST_NAME,Bld.Address,M.ADDRESS,D.DOB, '0' AS S.SALARY 
    from HW1_PERSON M 
    inner join HW1_BUILDING Bld 
    ON M.id = Bld.id 
    INNER JOIN HW1_PERSON M 
    ON Bld.id = M.id 
    INNER JOIN HW1_PERSON M 
    ON M.id = Bld.id 
    Inner JOIN HW1_BUILDING Bld 
    ON Bld.id = M.id 
    INNER JOIN HW1_BUILDING C 
    ON M.id = C.id 
    INNER JOIN HW1_PERSON D 
    ON M.id = D.id 
    UNION ALL 
    SELECT Bld.id,C.code,M.FIRST_NAME,M.LAST_NAME,Bld.Address,M.ADDRESS,D.DOB,S.SALARY FROM HW1_STAFF S 
    where S.SALARY = NULL 
    ; 

我第一個查詢列是不存在的S.SALARY因此設置默認爲'0'或''

Answer 2

首先，您在這裏做了一些不必要的連接。

你寫

from HW1_PERSON M 
inner join HW1_BUILDING Bld 
ON M.id = Bld.id 
INNER JOIN HW1_PERSON M 
ON Bld.id = M.id 
INNER JOIN HW1_PERSON M 
ON M.id = Bld.id 
Inner JOIN HW1_BUILDING Bld 
ON Bld.id = M.id 
INNER JOIN HW1_BUILDING C 
ON M.id = C.id 
INNER JOIN HW1_PERSON D 
ON M.id = D.id 

，但如果你這樣寫的，那麼這將是足夠

from HW1_PERSON M 
inner join HW1_BUILDING Bld 
ON M.id = Bld.id 
INNER JOIN HW1_BUILDING C 
ON M.id = C.id 

而且，你都用了M和D作爲同桌HW1_PERSON的別名 - 這在執行查詢時導致錯誤

其次，如評論中所述，您的第一個查詢不包含S.SALARY從HW1_STAFF列。從你的表格結構來看，我認爲你可以在你的第一個查詢中這樣做。

SELECT Bld.id,C.code,M.FIRST_NAME,M.LAST_NAME,Bld.Address,M.ADDRESS,M.DOB,S.SALARY 
from HW1_PERSON M 
inner join HW1_BUILDING Bld 
ON M.id = Bld.id 
INNER JOIN HW1_BUILDING C 
ON M.id = C.id 
INNER JOIN HW1_STAFF S 
ON S.PERSON_ID = M.id 

而且，在你的第二個查詢，您在S.SALARY搜索NULL，但你HW1_STAFF表的定義，該列將不能爲空。所以，在第二個查詢中，你不會得到任何結果。也許你應該該查詢改變 - 以這樣的

SELECT Bld.id,C.code,M.FIRST_NAME,M.LAST_NAME,Bld.Address,M.ADDRESS,D.DOB,S.SALARY FROM HW1_STAFF S 
where S.END_DATE = NULL 

然後，整個查詢會是這個樣子

SELECT Bld.id,C.code,M.FIRST_NAME,M.LAST_NAME,Bld.Address,M.ADDRESS,M.DOB,S.SALARY 
from HW1_PERSON M 
inner join HW1_BUILDING Bld 
ON M.id = Bld.id 
INNER JOIN HW1_BUILDING C 
ON M.id = C.id 
INNER JOIN HW1_STAFF S 
ON S.PERSON_ID = M.id 
UNION ALL 
SELECT Bld.id,C.code,M.FIRST_NAME,M.LAST_NAME,Bld.Address,M.ADDRESS,M.DOB,S.SALARY FROM HW1_STAFF S 
where S.END_DATE = NULL 
;