的Oracle SQL場

Question

我在SQL新手和有問題希望你能幫助我：

的Oracle 10g

表ACCOUNT

 
+----------+----------+ 
| ACCOUNTID| LBKEY | 
+----------+----------+ 
|  ... | ...  | 
|  254 | value254 | 
|  ... | ...  | 
|  401 | value401 | 
|  ... | ...  | 
|  405 | value405 | 
+----------+----------+ 

交叉引用表

 
+----------+----------+----------+--------+ 
| IDTABLE2 | ACCOUNTID| OIDID | VALUE | 
+----------+----------+----------+--------+ 
|  ... | ...  | ...  | ... | 
|  475 | 401  | 4  | 40000 | 
|  476 | 405  | 4  | 35000 | 
|  ...| ...  | ...  | ... | 
|  3000 | 254  | 5  | PARIS | 
|  3001 | 401  | 5  | LONDON | 
|  3002 | 405  | 5  | SYDNEY | 
|  ...| ...  | ...  | ... | 
+----------+----------+----------+--------+ 

表OID

 
+----------+-------------+-------------+ 
| OIDID |  OID  | DESCRIPTION | 
+----------+-------------+-------------+ 
|  1 | x   | x   | 
|  2 | x   | x   | 
|  3 | x   | x   | 
|  4 | 1.3.6.1.4.1 | Post Code | 
|  5 | 1.3.6.1.4.2 | City  | 
|  6 | x   | x   | 
|  7 | x   | x   | 
|  8 | x   | x   | 
|  9 | x   | x   | 
|  10 | x   | x   | 
+----------+-------------+-------------+ 

預期結果

約束：所有ACCOUNT（LBKEY）誰擁有交叉引用表

一個郵政編碼（OID 4）或城市代碼（OID 5）

 
+----------+-------------+-------------+ 
| LBKEY | POST CODE | CITY  | 
+----------+-------------+-------------+ 
| value254 | null  | PARIS  | 
| value401 | 40000  | LONDON  | 
| value405 | 35000  | SYDNEY  | 
+----------+-------------+-------------+ 

Answer 1

三種不同的方式：

SQL Fiddle

的Oracle 11g R2架構設置：

CREATE TABLE ACCOUNT (ACCOUNTID, LBKEY) AS 
      SELECT 254, 'value254' FROM DUAL 
UNION ALL SELECT 401, 'value401' FROM DUAL 
UNION ALL SELECT 405, 'value405' FROM DUAL 
UNION ALL SELECT 406, 'value406' FROM DUAL; 

CREATE TABLE CrossReference (IDTABLE2, ACCOUNTID, OIDID, VALUE) AS 
      SELECT 475, 401, 4, '40000' FROM DUAL 
UNION ALL SELECT 476, 405, 4, '35000' FROM DUAL 
UNION ALL SELECT 3000, 254, 5, 'PARIS' FROM DUAL 
UNION ALL SELECT 3001, 401, 5, 'LONDON' FROM DUAL 
UNION ALL SELECT 3002, 405, 5, 'SYDNEY' FROM DUAL 
UNION ALL SELECT 4000, 406, 6, 'x' FROM DUAL; 


CREATE TABLE OID (OIDID, OID, DESCRIPTION) AS 
      SELECT 1, 'x', 'x' FROM DUAL 
UNION ALL SELECT 2, 'x', 'x' FROM DUAL 
UNION ALL SELECT 3, 'x', 'x' FROM DUAL 
UNION ALL SELECT 4, '1.3.6.1.4.1', 'Post Code' FROM DUAL 
UNION ALL SELECT 5, '1.3.6.1.4.2', 'City' FROM DUAL 
UNION ALL SELECT 6, 'x', 'x' FROM DUAL 
UNION ALL SELECT 7, 'x', 'x' FROM DUAL 
UNION ALL SELECT 8, 'x', 'x' FROM DUAL 
UNION ALL SELECT 9, 'x', 'x' FROM DUAL 
UNION ALL SELECT 10, 'x', 'x' FROM DUAL; 

查詢1：

SELECT LBKEY, 
     MAX(CASE OIDID WHEN 4 THEN VALUE END) AS "Post Code", 
     MAX(CASE OIDID WHEN 5 THEN VALUE END) AS "City" 
FROM ACCOUNT a 
     INNER JOIN 
     CrossReference c 
     ON (a.ACCOUNTID = c.ACCOUNTID) 
WHERE c.OIDID IN (4, 5) 
GROUP BY LBKEY 

Results：

| LBKEY | POST CODE | CITY | 
|----------|-----------|--------| 
| value254 | (null) | PARIS | 
| value405 |  35000 | SYDNEY | 
| value401 |  40000 | LONDON | 

查詢2：

WITH data AS (
    SELECT LBKEY, 
     (SELECT VALUE 
      FROM CrossReference c 
      WHERE c.ACCOUNTID = a.ACCOUNTID 
      AND c.OIDID = 4) AS "Post Code", 
     (SELECT VALUE 
      FROM CrossReference c 
      WHERE c.ACCOUNTID = a.ACCOUNTID 
      AND c.OIDID = 5) AS "City" 
    FROM ACCOUNT a 
) 
SELECT * 
FROM data 
WHERE "Post Code" IS NOT NULL 
OR  "City"  IS NOT NULL 

Results：

| LBKEY | POST CODE | CITY | 
|----------|-----------|--------| 
| value254 | (null) | PARIS | 
| value401 |  40000 | LONDON | 
| value405 |  35000 | SYDNEY | 

查詢3：

SELECT LBKEY, 
     c1.VALUE AS "Post Code", 
     c2.VALUE AS City 
FROM ACCOUNT a 
     LEFT OUTER JOIN 
     (SELECT ACCOUNTID, VALUE FROM CrossReference WHERE OIDID = 4) c1 
     ON (c1.ACCOUNTID = a.ACCOUNTID) 
     LEFT OUTER JOIN 
     (SELECT ACCOUNTID, VALUE FROM CrossReference WHERE OIDID = 5) c2 
     ON (c2.ACCOUNTID = a.ACCOUNTID) 
WHERE c1.VALUE IS NOT NULL 
OR  c2.VALUE IS NOT NULL 

Results：

| LBKEY | POST CODE | CITY | 
|----------|-----------|--------| 
| value254 | (null) | PARIS | 
| value401 |  40000 | LONDON | 
| value405 |  35000 | SYDNEY | 

Answer 2

我認爲這可能爲你工作：

select 
     lbkey, 
     cross_post.value as postcode, 
     cross_city.value as city 
from 
     ACCOUNT a, 
     cross cross_city, 
     cross cross_post, 
where 
     a.accountid=cross_city.accountid(+) and 
     a.accountid=cross_post.accountid(+) and 
     nvl(cross_city.oidid,5)=5 and 
     nvl(cross_post.oidid,4)=4 and 
     (cross_city.oidid is not null or cross_post.oidid is not null) 

這樣做的