Oracle SQL - 隔離孤立數據

Question

我有一個應用程序可以跟蹤文件何時「試圖」從一臺服務器移動到另一臺服務器，以及它何時「成功」或「失敗」。「嘗試」應該總是與「成功」或「失敗」配對。但是，我遇到了孤立的企圖...意味着已有嘗試沒有任何成功或失敗的報道。從another question我問，我能夠隔離特別是孤兒的e_ids。但是，我不想在最終輸出中返回「非孤兒」傳輸。考慮下面的示例輸出：

在上面的輸出，例如，E_ID 具有完成傳輸（嘗試 - >成功）在時間2016年5月23日下午11點37分09秒。我不想看見這個。再次，e_id 在2016年5月25日1:28:36 PM時已完成傳輸（嘗試 - >失敗）。我也不想看到這個。我只希望看到的孤立的傳輸，具有結果集看起來像這樣：

這可能是值得指出的是，對方（在一秒鐘內發生，因此，爲什麼在首先完成傳輸樣本輸出日期顯示爲相同，實際上它們之間的差異爲毫秒）。

最後，我查詢迄今如下

--This query shows all data for all contact_id's known to be an orphan 
SELECT * FROM 
(
    SELECT 
     d.* 
    FROM 
     (
      SELECT e_id, COUNT(*) AS attempts FROM e_table 
      WHERE e_comment LIKE '%attempting%' 
      AND e_date >= '23-MAY-2016' 
      AND e_date <= '26-MAY-2016' 
      GROUP BY e_id 
     ) a 
     FULL OUTER JOIN 
     (
      SELECT e_id, COUNT(*) AS successes FROM e_table 
      WHERE e_comment LIKE '%successful%' 
      AND e_date >= '23-MAY-2016' 
      AND e_date <= '26-MAY-2016' 
      GROUP BY e_id 
     ) s 
      ON s.e_id = a.e_id 
     FULL OUTER JOIN 
     (
      SELECT e_id, COUNT(*) AS failures FROM e_table 
      WHERE e_comment LIKE '%failed%' 
      AND e_date >= '23-MAY-2016' 
      AND e_date <= '26-MAY-2016' 
      GROUP BY e_id 
     ) f 
      ON f.e_id = COALESCE(a.e_id, s.e_id) 
     FULL OUTER JOIN 
     (
      SELECT * FROM e_table 
      WHERE e_date >= '23-MAY-2016' 
      AND e_date <= '26-MAY-2016' 
     ) d 
      ON a.e_id = d.e_id   
    WHERE 
     COALESCE(attempts, 0) <> COALESCE(successes, 0) + COALESCE(failures, 0) 
) 
MINUS 
(
    --This is where I'm stuck. I figure, with a MINUS, I can remove the 
    --cases with completed transmissions, thus showing ONLY the orphans. 
) 

任何幫助是極大的讚賞。

Answer 1

以下查詢完成我所需要的。而不是使用原始問題中指定的範圍，我拉「昨天的」數據：

SELECT et.* FROM 
(
    SELECT ce_id, e_id FROM e_table et 
    WHERE e_comment LIKE ("attempt") 
    AND e_date >= TO_DATE(TRUNC(SYSDATE-1)) 
    AND e_date <= TO_DATE(TRUNC(SYSDATE-1) || ' 23:59:59', 'DD-MON-YY HH24:MI:SS') 
    AND NOT EXISTS 
    (
     SELECT ce_id, e_id FROM e_table ett 
     WHERE e_comment LIKE ("success") OR e_comment LIKE ("failure") 
     AND et.e_id = ett.e_id 
     AND ett.ce_id > et.ce_id 
    ) 
) orphans, e_table et 
WHERE orphans.ce_id = et.ce_id 
AND orphans.e_id = et.e_id 
ORDER BY et.ce_id ASC; 

Answer 2

這是一個不需要任何連接的解決方案;相反，它使用分析函數LEAD。

甲骨文設置：

CREATE TABLE e_table (ce_id, e_id, e_comment, e_date) AS 
SELECT '472', '125', 'is attempting to move', TIMESTAMP '2016-05-23 09:49:10' FROM DUAL UNION ALL 
SELECT '678', '125', 'is attempting to move', TIMESTAMP '2016-05-23 11:37:09' FROM DUAL UNION ALL 
SELECT '724', '125', 'has successfully moved', TIMESTAMP '2016-05-23 11:37:09' FROM DUAL UNION ALL 
SELECT '983', '034', 'is attempting to move', TIMESTAMP '2016-05-24 17:04:35' FROM DUAL UNION ALL 
SELECT '643', '672', 'is attempting to move', TIMESTAMP '2016-05-25 13:28:36' FROM DUAL UNION ALL 
SELECT '026', '672', 'failed to move',   TIMESTAMP '2016-05-25 13:28:36' FROM DUAL UNION ALL 
SELECT '087', '672', 'is attempting to move', TIMESTAMP '2016-05-24 18:33:35' FROM DUAL; 

查詢：

SELECT ce_id, 
     e_id, 
     e_comment, 
     e_date 
FROM (
    SELECT e.*, 
     LEAD(e_comment) 
      OVER (PARTITION BY e_id 
        ORDER BY e_date, 
          DECODE(e_comment, 'is attempting to move', 1, 2) 
       ) AS next_comment 
    FROM e_table e 
) 
WHERE (next_comment IS NULL OR next_comment = 'is attempting to move') 
AND e_comment = 'is attempting to move'; 

輸出：

CE_ID E_ID E_COMMENT    E_DATE      
----- ---- ---------------------- ----------------------------- 
983 034 is attempting to move 2016-05-24 17:04:35.000000000 
472 125 is attempting to move 2016-05-23 09:49:10.000000000 
087 672 is attempting to move 2016-05-24 18:33:35.000000000