1
有一個查詢:如何合併兩個生成的表使用由'a'字段的組由'b'字段的最大值?
select `privmsgs_id`, `contact`, `privmsgs_date`, `contentType` from (
(
select max(`privmsgs_id`) as `privmsgs_id`, `contact`, max(`privmsgs_date`) as `privmsgs_date`, `contentType` from (
(
select `privmsgs_from_userid` as `contact`, `privmsgs_id`, `privmsgs_date`, 'message' as `contentType`
from `privmsgs_table`
where `privmsgs_to_userid` = 305026
) union (
select `privmsgs_to_userid` as `contact`, `privmsgs_id`, `privmsgs_date`, 'message' as `contentType`
from `privmsgs_table`
where `privmsgs_from_userid` = 305026
)
) as `tmp` group by `contact` order by `privmsgs_date` desc
) union (
select max(`privmsgs_id`) as `privmsgs_id`, `contact`, max(`privmsgs_date`) as `privmsgs_date`, `contentType` from (
(
select `from_userid` as `contact`, `id` as `privmsgs_id`, `date` as `privmsgs_date`, 'postcard' as `contentType`
from `postcards_table`
where `to_userid` = 305026
) union (
select `to_userid` as `contact`, `id` as `privmsgs_id`, `date` as `privmsgs_date`, 'postcard' as `contentType`
from `postcards_table`
where `from_userid` = 305026
)
) as `tmp1` group by `contact` order by `privmsgs_date` desc
)
) as `rTmp` order by `privmsgs_date` desc;
有兩個表tmp
和tmp1
工會合並,但增加了一倍場contact
:
privmsgs_id contact privmsgs_date contentType
21490780 7070 1315207813 message
21556868 7070 1315215266 postcard
21226460 7754 1312025735 message
21539085 15588 1314615528 postcard
21489812 15588 1315208838 message
所以,我只需要最後一個記錄(消息或明信片 - 不沒有問題)和最後一個記錄的ID(有問題 - 我可以在郵件和明信片單獨獲取最大(id),但不能在合併表中完成):
privmsgs_id contact privmsgs_date contentType
21556868 7070 1315215266 postcard
21226460 7754 1312025735 message
21489812 15588 1315208838 message
原因,爲什麼我不通過簡化查詢來做到這一點,因爲我需要特定數量的結果,因此,我只能通過一個查詢來完成此操作。
明信片和消息從分開的表中獲得,所以較舊的postard(按日期)的ID可能小於先前的消息ID。有問題 - 我不能通過不同的ID排序兩個不同的表。 – extempl
我需要通過按「聯繫人」對記錄進行分組並按max(日期)進行排序來獲取實際ID。這是做到這一點的唯一方法,但我不知道如何。 – extempl