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我加入這個社區是因爲它看起來很棒，而且我是一個新的編碼器，所以我想通過遵循這樣一個好的社區的建議來嘗試和快速改進。 :)Lua中的條件分支不是沒有明確的理由嗎？
我有一個關於lua編碼的問題 - 現在，我使用Corona SDK和Sublime Text 3編寫移動啓動畫面和標題屏幕。我從titleScreen = false開始，這樣我就可以運行啓動畫面的代碼，使其成爲現實。但是，當我完成啓動屏幕的代碼並使titleScreen = true時，titlescreen的條件分支不起作用！請幫我:(我已經做噸的測試，但不能揣摩出我的錯誤在於
這裏是我的代碼：
titleScreen = false
local logo = display.newImage("logo.png", 155, 275)
logo.alpha = 0
local function makeMenuTrue()
logo:removeSelf()
print("menu should be TRUE")
print("WHY DOESN'T IT WORK")
titleScreen = true
end
local function fadeOut()
transition.to(logo, {time = 2000, alpha = 0, onComplete = makeMenuTrue})
end
transition.to(logo, {time = 2000, alpha = 1, onComplete = fadeOut})
if (titleScreen == true) then
print("NOW IT'S TRUE")
local mainTheme = audio.loadSound ("mainTheme.wav")
audio.play(mainTheme)
display.setStatusBar(display.HiddenStatusBar)
local background1 = display.newImage("Title.png", 155, 275)
local flare = display.newImage("flare2.png", 40, 30)
flare.xScale = .5
flare.yScale = .5
local flare2 = display.newImage("flare2.png", 400, 70)
flare2.xScale = .6
flare2.yScale = .6
local flare3 = display.newImage("flare2.png", 400, 70)
flare2.xScale = .4
flare2.yScale = .4
local function moveFlare1()
transition.to(flare, {time=2000, x = math.random(-100, 450), y = math.random(-100, 700), onComplete = moveFlare1})
end
local function moveFlare2()
transition.to(flare2, {time=2000, x = math.random(-100, 450), y = math.random(-100, 700), onComplete = moveFlare2})
end
local function moveFlare3()
transition.to(flare3, {time=2000, x = math.random(-100, 450), y = math.random(-100, 700), onComplete = moveFlare3})
end
transition.to(flare, {time=2000, x = math.random(-100, 450), y = math.random(-100, 700), onComplete = moveFlare1})
transition.to(flare2, {time=2500, x = math.random(-100, 450), y = math.random(-100, 700), onComplete = moveFlare2})
transition.to(flare3, {time=2000, x = math.random(-100, 450), y = math.random(-100, 700), onComplete = moveFlare3})
--[[local textbox = display.newRect(160, 214, 320, 90)
textbox:setFillColor(.1, .1, .1, .6)
]]
local textbox = display.newImage("MessageBack2.png", 155, 254, 320, 90)
textbox.yScale = .7
local textline = display.newImage("flare2.png", 0, 228)
textline.xScale = 20
textline.yScale = .3
local textOption = 1
local prompt1 = display.newText ("Start Game", 155, 230, "Goudy Old Style", 20)
local prompt2 = display.newText ("Continue", 155, 255, "Goudy Old Style", 20)
local prompt3 = display.newText ("Exit Game", 155, 280, "Goudy Old Style", 20)
prompt1:setFillColor(0,0,0)
local function textShrink()
transition.to(textline, {time = 150, yScale = .3})
end
local function moveTextBox()
if (textOption == 1) then
textOption = 2
transition.to(textline, {time = 200, y = 253, onComplete = textShrink})
prompt2:setFillColor(0,0,0)
prompt1:setFillColor(1,1,1)
else
if (textOption == 2) then
textOption = 3
transition.to(textline, {time = 200, y = 278, onComplete = textShrink})
prompt3:setFillColor(0,0,0)
prompt2:setFillColor(1,1,1)
else
if (textOption == 3) then
textOption = 1
transition.to(textline, {time = 200, y = 228, onComplete = textShrink})
prompt1:setFillColor(0,0,0)
prompt3:setFillColor(1,1,1)
end
end
end
end
local function expandText()
if (textOption == 1) then
print("object 1 has been tapped????")
else
if (textOption == 2) then
print("object 2 has been tapped????")
else
if (textOption == 3) then
print("object 3 has been tapped????")
end
end
end
end
transition.to(textline, {time = 150, yScale = .5, 0, onComplete = moveTextBox})
textbox:addEventListener("tap", expandText)
else
print("lmao no it's not true")
end
任何幫助深表感謝！
'腳本運行時調用'transition.to（）'，完成時調用'fadeOut（）'，完成時調用'makeMenuTrue（）'。 –
'makeMenuTrue'將被調用。但是'if'語句在腳本重載之前不會被調用，並且如果它將在'fadeout（）'調用後重新加載，那麼'titleScreen'將在腳本的開始處被擦除。 – Vlad
哇，謝謝！我在使用「onComplete」進行一對夫妻轉換後確實調用了「makeMenuTrue」，但我明白了爲什麼這是真的。我可以要求更多關於「何時/如果你再次加載/運行它，你有無條件地執行titleScreen = false的規範，所以你不能讓titleScreen存儲任何可以被以前的makeMenuTrue調用更新的信息」部分？我不太明白 - 不應該將執行爲false的值更新爲makeMenuTrue調用？什麼阻止？對不起，如果我不明白，有時這個論壇的語言對我來說很複雜:) –