easymock意外的行爲

我不知道我在做什麼錯在這裏。我在代碼中出現了這個錯誤，所以我編寫了一個簡單的例子來試圖找出錯誤所在。easymock意外的行爲

我有一個ClassA，這取決於兩個服務ServiceA和ServiceB，我試圖測試ClassA，並嘲笑ServiceA和ServiceB。

/** 
* Last edited by: $Author: cg $ 
* on: $Date: 17 Jun 2011 11:36:25 $ 
* Filename: $RCSfile: ClassA.java,v $ 
* Revision: $Revision: $ 
*/ 
package easy; 

import java.util.HashMap; 


/** 
* 
* @version $Revision: $, $Date: 17 Jun 2011 11:36:25 $ 
*/ 
public class ClassA { 
    private ServiceA serviceA; 
    private ServiceB serviceB; 
    public ClassA(ServiceA a, ServiceB b) { 
     this.serviceA = a; 
     this.serviceB = b;   
    } 
    public String process(String p) { 
     HashMap<String,String> a = serviceA.getServiceA(p); 
     String ret = serviceB.getServiceB(a); 
     return ret; 
    } 
} 


interface ServiceA{ 
    HashMap<String,String>getServiceA(String s); 
} 

interface ServiceB{ 
    String getServiceB(HashMap<String,String> p); 
}

我的測試如下：

/** 
* Last edited by: $Author: cg $ 
* on: $Date: 17 Jun 2011 11:43:05 $ 
* Filename: $RCSfile: ClassATest.java,v $ 
* Revision: $Revision: $ 
*/ 
package easy; 

import static org.easymock.EasyMock.eq; 
import static org.easymock.EasyMock.expect; 

import java.util.HashMap; 

import junit.framework.Assert; 

import org.easymock.EasyMock; 
import org.easymock.IMocksControl; 
import org.junit.Test; 
/** 
* 
* @version $Revision: $, $Date: 17 Jun 2011 11:43:05 $ 
*/ 
public class ClassATest { 

    @Test 
    public void testProcess() { 
     IMocksControl mockery = EasyMock.createControl(); 
     mockery.resetToStrict(); 
     mockery.checkOrder(true); 

     ServiceA serviceA = EasyMock.createMock("ServiceA",ServiceA.class); 
     ServiceB serviceB = EasyMock.createMock("ServiceB",ServiceB.class); 

     ClassA a = new ClassA(serviceA, serviceB); 

     String myParam = "My Test"; 

     HashMap<String,String> retFromServiceA = new HashMap<String,String>(); 
     retFromServiceA.put("my", "name"); 
     expect(serviceA.getServiceA(eq(myParam))).andReturn(retFromServiceA); 
     expect(serviceB.getServiceB(retFromServiceA)).andReturn(myParam); 

     mockery.replay(); 
     String actual = a.process(myParam); 
     mockery.verify(); 

     Assert.assertEquals(myParam, actual); 
    } 
}

結果是失敗，因爲實際收益是零。

我試圖調試到代碼中，我認識到，雖然在我的期望我說我希望ServiceA.getServiceA返回retFromServiceA，事實並非如此。它返回null。

任何想法？

來源

2011-06-17 Charbel

ServiceA和ServiceB而不使用嘲笑控制創建，因此應使用：執行該處理方法

EasyMock.replay(serviceA, serviceB);

之前

來源

2011-06-17 11:17:36 Klarth

easymock意外的行爲

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