彈跳圖像的動畫

Question

我想動畫像彈跳一樣的圖像。我能夠反彈它，但我不能推回來。 我使用這個代碼：

[UIView beginAnimations:nil context:NULL]; 
[UIView setAnimationDuration:2.0f]; 
hair.transform = CGAffineTransformMakeScale(3.0, 3.0); 
[UIView commitAnimations]; 

請幫我..我早上結構在這一點上並沒有能夠解決這個problem.Please幫助我。

Answer 1

請注意，從UIView reference：

這種方法的使用在iPhone OS 4.0及更高版本氣餒。您應該使用基於塊的動畫方法。

所以你的情況你可能想實現這樣的：

[UIView animateWithDuration:2.0 animations:^(void) { 
    hair.transform = CGAffineTransformMakeScale(2.0, 2.0); 
} completion:^(BOOL finished) { 
    if(finished){ 
     [UIView animateWithDuration:2.0 animations:^(void) { 
      hair.transform = CGAffineTransformMakeScale(0.5, 0.5); 
     }]; 
    } 
}]; 

Answer 2

使用的代碼，這幾行獲得動畫的圖像一樣彈跳。

imgView.transform = CGAffineTransformScale(CGAffineTransformIdentity, 0.001, 0.001); 

//imgView is your UIImageView where you set an image 

[self.view addSubview:imgView]; 

[UIView animateWithDuration:0.3/1.5 animations:^{ 
    imgView.transform = CGAffineTransformScale(CGAffineTransformIdentity, 1.1, 1.1); 
} completion:^(BOOL finished) { 
[UIView animateWithDuration:0.3/2 animations:^{ 
    imgView.transform = CGAffineTransformScale(CGAffineTransformIdentity, 0.9, 0.9); 
} completion:^(BOOL finished) { 
    [UIView animateWithDuration:0.3/2 animations:^{ 
     imgView.transform = CGAffineTransformIdentity;        
    }]; 
}]; 
}]; 

感謝

Answer 3

您可以使用此代碼，您只需要調用其中的一個，他們會打電話給對方自動

- （無效）animateZoomOut {

[UIView animateWithDuration:1 
         delay:0 
        options:UIViewAnimationOptionTransitionNone 
       animations:^ { 
        self.imgGift.transform = CGAffineTransformMakeScale(0.5, 0.5); 
       }completion:^(BOOL finished) { 
        [self animateGiftZoomIn]; 
       }]; 

} - （void）animateZoomIn {

[UIView animateWithDuration:1 
         delay:0 
        options:UIViewAnimationOptionTransitionNone 
       animations:^ { 
        self.imgGift.transform = CGAffineTransformMakeScale(1, 1); 
       }completion:^(BOOL finished) { 
        [self animateGiftZoomOut]; 
       }]; 

}