我有兩個表一個是 'tb_student' 等是 'tb_fees'如何在一個查詢中進行分組和排序?
爲 'tb_student'
CREATE TABLE `tb_student` (
`id` int(11) NOT NULL auto_increment,
`name` varchar(255) NOT NULL,
`email` varchar(255) NOT NULL,
`class` varchar(255) NOT NULL,
`created_on` datetime NOT NULL default '0000-00-00 00:00:00',
PRIMARY KEY (`id`)
)
創建查詢創建查詢 'tb_fees'
CREATE TABLE `tb_fees` (
`id` int(11) NOT NULL auto_increment,
`email` varchar(255) NOT NULL,
`amount` varchar(255) NOT NULL,
`created_on` datetime NOT NULL default '0000-00-00 00:00:00',
PRIMARY KEY (`id`)
)
在第一個表我存儲學生的詳細信息,並在其他表中存儲費用詳情
我想從'tb_student'中選擇學生的詳細信息,從「tb_fees只針對那些學生,其在6級
所以我想這
SELECT *
FROM tb_student s INNER JOIN
tb_fees f on
s.email =f.email
WHERE s.class = 6 GROUP BY s.email ORDER BY f.created_on DESC
這會給結果只有第一個創建如何獲得最後創造的價值
收費表中添加費
insert into `tb_fees`(`id`,`email`,`amount`,`created_on`) values (5,'[email protected]','5000','2013-05-01 14:20:15');
insert into `tb_fees`(`id`,`email`,`amount`,`created_on`) values (6,'[email protected]','5000','2013-05-02 14:20:23');
insert into `tb_fees`(`id`,`email`,`amount`,`created_on`) values (7,'[email protected]','5000','2013-05-03 14:20:30');
insert into `tb_fees`(`id`,`email`,`amount`,`created_on`) values (8,'[email protected]','5000','2013-05-29 14:20:35');
insert into `tb_fees`(`id`,`email`,`amount`,`created_on`) values (9,'[email protected]','5000','2013-05-30 14:20:39');
insert into `tb_fees`(`id`,`email`,`amount`,`created_on`) values (10,'[email protected]','5000','2013-05-30 14:36:13');
insert into `tb_fees`(`id`,`email`,`amount`,`created_on`) values (11,'[email protected]','5000','2013-05-30 14:36:15');
insert into `tb_fees`(`id`,`email`,`amount`,`created_on`) values (12,'[email protected]','5000','2013-05-30 14:36:15');
學生表值
insert into `tb_student`(`id`,`name`,`email`,`class`,`created_on`) values (5,'Ram','[email protected]','6','2013-04-30 14:00:56');
insert into `tb_student`(`id`,`name`,`email`,`class`,`created_on`) values (6,'Sam','[email protected]','6','2013-03-30 14:01:30');
insert into `tb_student`(`id`,`name`,`email`,`class`,`created_on`) values (7,'Nimmy','[email protected]','7','2013-04-30 13:59:59');
insert into `tb_student`(`id`,`name`,`email`,`class`,`created_on`) values (8,'jak','[email protected]','6','2013-03-30 14:07:32');
insert into `tb_student`(`id`,`name`,`email`,`class`,`created_on`) values (9,'rose','[email protected]','5','2013-04-30 14:07:51');
謝謝
給你給人以樣本記錄你想要的結果? –
在此有任何錯誤? – Kangkan
它不會總是給你第一個創建,雖然可能會。它給你的是未定義的。 – Kickstart