在一個查詢中對組進行排序和計數

Question

我正在試圖在GROUP,SORT和COUNT中對我的名爲「商品」的表進行查詢。

這裏是我的MySql表的簡化：

family sub_family name  detailed_name 
Agro Grains  Wheat  Wheat per 1 mt 
Agro Grains  Corn  Corn per 1 mt 
Agro Grains  Sugar  Sugar per 1 mt 
Agro Fruits  Apple  Apple red 
Agro Fruits  Apple  Apple green 
Agro Fruits  Apple  Apple yellow 
Agro Fruits  Lemon  Lemon classic 
Wood Tree  Lemon  Lemon in logs 
Wood Tree  Oak   Oak in logs 
Wood Tree  Epicea  Epicea in logs 
Wood Packaging Kraftliner Krafliner 3mm 

我想：

1. GROUP通過name
2. SORT通過family，sub_family和最後name
3. COUNT的ñ行每個family，sub_family然後name的umbers（在同一個sub_family）

到目前爲止，我能夠做到的一切，但COUNT在同一sub_family。

事實上，下面的查詢：

SELECT 
    TableC.family, 
    TableC.NbrFamily, 
    TableB.sub_family, 
    TableB.NbrSubFamily, 
    TableA.name, 
    TableA.NbrName 
FROM 
(
    SELECT 
     family, 
     sub_family, 
     name, 
     COUNT(DISTINCT commodities.id) AS NbrName 
    FROM commodities GROUP BY name 
) TableA 
INNER JOIN 
(
    SELECT 
     sub_family, 
     COUNT(DISTINCT commodities.id) AS NbrSubFamily 
    FROM commodities GROUP BY sub_family 
) TableB 
ON (TableA.sub_family = TableB.sub_family) 
INNER JOIN 
(
    SELECT 
     family, 
     COUNT(DISTINCT commodities.id) AS NbrFamily 
    FROM commodities GROUP BY family 
) TableC 
ON (TableA.family = TableC.family) 
GROUP BY TableA.name 
ORDER BY TableA.family,TableA.sub_family,TableA.name 

其結果如下：

family NbrFamily sub_family NbrSubFamily name  NbrName 
Agro 7   Grains  3    Wheat  1  
Agro 7   Grains  3    Corn  1   
Agro 7   Grains  3    Sugar  1  
Agro 7   Fruits  4    Apple  3 
Agro 7   Fruits  4    Lemon  2 
Wood 4   Tree  3    Lemon  2 
Wood 4   Tree  3    Oak   1  
Wood 4   Tree  3    Epicea  1 
Wood 4   Packaging 1    Kraftliner 1 

你可以看到，NbrName計數檸檬 2次，但我想它只能算它1次因爲一個檸檬是水果sub_family另一個在樹sub_family。

[更新]：這是我想要的結果：

family NbrFamily sub_family NbrSubFamily name  NbrName 
    Agro 7   Grains  3    Wheat  1  
    Agro 7   Grains  3    Corn  1   
    Agro 7   Grains  3    Sugar  1  
    Agro 7   Fruits  4    Apple  3 
    Agro 7   Fruits  4    Lemon  1 
    Wood 4   Tree  3    Lemon  1 
    Wood 4   Tree  3    Oak   1  
    Wood 4   Tree  3    Epicea  1 
    Wood 4   Packaging 1    Kraftliner 1 

Answer 1

只是我的猜測是什麼，因爲它帶來期望的結果，你所要求的http://sqlfiddle.com/#!9/e9206/16

：

SELECT A.family, C.NbrFamily,A.sub_family,B.NbrSubFamily,A.name,COUNT(A.Name) 
FROM commodities as A 
LEFT JOIN (
    SELECT family,sub_family,COUNT(Name) AS NbrSubFamily 
    FROM commodities 
    GROUP BY family,sub_family 
) B 
ON A.sub_family = B.sub_family 
    AND A.family = B.family 
LEFT JOIN (
    SELECT family,COUNT(Name) AS NbrFamily 
    FROM commodities 
    GROUP BY family 
) C 

ON A.family = C.family 
GROUP BY A.family,A.sub_family,A.name 
ORDER BY A.id