得到每負載＃，只有前20

Question

的最大計數在使用下面的代碼：

SELECT  SUM(LD_NUM) AS Expr1, LD_NUM 
FROM   Bale 
GROUP BY LD_NUM 

returns Expr1 = 74987 and LD_NUM = 4411 
returns Expr1 = 61768 and LD_NUM = 4412 
returns Expr1 = 75021 and LD_NUM = 4413 

等。

如果我四千四百十一分之七萬四千九百八十七= 17，這給了我每LD_NUM

計數

有沒有方法可以返回關係（17,4411），（14,4412），（17,4413） ，並通過'Expr1'獲得或排序前20位？

希望這可以從此。

Answer 1

SELECT TOP 20 SUM(LD_NUM) AS Expr1, LD_NUM, COUNT(LD_NUM) AS RecordCount 
    FROM Bale 
    GROUP BY LD_NUM 
    ORDER BY Expr1 DESC 

不知道你是否需要SUM用於任何其他目的。這可能是這麼簡單：

SELECT TOP 20 LD_NUM, COUNT(LD_NUM) AS RecordCount 
    FROM Bale 
    GROUP BY LD_NUM 
    ORDER BY RecordCount DESC 

Answer 2

你不需要做任何的計算才能獲得計數，

count(LD_NUM) 

是所有的需要

Answer 3

試試這個

SELECT TOP 20 Expr1/LD_NUM,LD_NUM 
FROM 
(
    SELECT  SUM(LD_NUM) AS Expr1, LD_NUM 
    FROM   Bale 
    GROUP BY LD_NUM 
) xx 
ORDER BY xx.expr1