的Python 3.2：類型錯誤：參數必須是int，或者有一個的fileno（）方法

Question

基本上我複製從計算器這些方法和修改他們爲我的必要性：

from http.client import HTTPConnection, HTTPSConnection 
import select 
connections = {} 


def request(method, url, body=None, headers={}, **kwargs): 
    scheme, _, host, path = url.split('/', 3) 
    h = connections.get((scheme, host)) 
    if h and select.select([h.sock], [], [], 0)[0]: 
     h.close() 
     h = None 
    if not h: 
     Connection = HTTPConnection if scheme == 'http:' else HTTPSConnection 
     h = connections[(scheme, host)] = Connection(host, **kwargs) 
    h.request(method, '/' + path, body, headers) 
    return h.getresponse() 


def urlopen(url, data=None, *args, **kwargs): 
    resp = request('POST' if data else 'GET', url, data, *args, **kwargs) 
    if resp.status == 400: 
     fileAccessed = resp.read() 
     if 'failed to open stream: Permission denied' in str(fileAccessed): 
      return "permission denied" 
     else: 
      return fileAccessed 
    else: 
     return "not found" 

現在我使用它們類似於此示例：

with open('addons.txt', 'r') as addonsFile: 
    for line in addonsFile: 
     addon = line.rstrip() 
     fileUrl = 'http://www.google.com/%s/ncr' % addon 
     response = urlopen(fileUrl) 

的程序得到第一插件，使所述第一請求細。在第二次迭代，我得到這個錯誤：計算器的

Traceback (most recent call last): 
    File "/root/add.py", line 45, in <module> 
    response = urlopen(fileUrl) 
    File "/root/add.py", line 26, in urlopen 
    resp = request('POST' if data else 'GET', url, data, *args, **kwargs) 
    File "/root/add.py", line 15, in request 
    if h and select.select([h.sock], [], [], 0)[0]: 
TypeError: argument must be an int, or have a fileno() method. 

尊敬的領主，請幫我糾正我的計劃！

Answer 1

是啊...所以...我不知道......我 刪除了，我得到了錯誤的部分：

if h and select.select([h.sock], [], [], 0)[0]: 
     h.close() 
     h = None 
    if not h: 

，現在一切正常。