stackflow新增,我希望我的問題可以幫助其他python新手。初學者:用elif控制流和語法錯誤
我試圖創建一個執行程序如下:1。 == secret_num產生1-10
2之間的隨機#詢問用戶猜測1-10 3之間用這個號碼,如果猜測= = secret_num向他們表示祝賀,並提供 4.帳戶重複猜測 5.讓他們知道,如果猜測是太高或太低
我知道這是ABC的東西爲它花了猜測number_guesses的數量(減去任何重複的猜測)很多人,但我有語法,縮進和控制流程的典型新程序員問題。現在我得到了elif guess == secret num的語法。否則,我無法獲得此代碼來解釋重複以挽救我的生命。我將不勝感激任何幫助。謝謝 。
import random
def game():
# generate a random number between 1 -100 and initiate repeat guess list
secret_num=random.randint(1,10)
# initiate duplicate list and number of guesses
already_guesses = []
number_guesses = 0
while True:
# ask for user guess
guess = int(input('Guess a number from 1-10> '))
# help with guesses and announce if it is correct number!
# catch someone if they submit the same number
if guess in already_guesses:
print ("You already guessed that number, try again")
already_guesses.append(guess)
number_guesses += 1
elif guess == secret_num:
print("whooohoo! you guessed it, my number is {}".format(secret_num))
print("It took you {} guesses".format(number_guesses - len([already_guesses])))
break
elif guess < secret_num:
print("You\'re getting hot, try a higher number")
else:
guess > secret_num
print("You\'re cold, try a lower number")
# ask if they want to play again
else:
play_again = input("Do you wanna play again? y/n")
if play_again != 'n':
game()
else:
print("Bah Bye!")
game()
的上面兩行需要縮進。 – neil