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我有我的表jquery解析的問題。我相信我此刻的分析是這樣的:它顯示<tbody>每行
<table id="qandatbl">
<thead>
<tr>
<th class="qid">Question No</th>
<th class="question">Question</th>
<th class="option">Option Type</th>
<th class="noofanswers">Number of Answers</th>
<th class="answer">Answer</th>
<th class="noofreplies">Number of Replies</th>
<th class="weight">Number of Marks</th>
<th class="image">Image</th>
<th class="video">Video</th>
<th class="audio">Audio</th>
</tr>
</thead>
<tbody>
<tr></tr>
</tbody>
<tbody>
<tr></tr>
</tbody>
<tbody>
<tr></tr>
</tbody>
</table>
它創建於各行的<tbody>
。相反,它應顯示一個<tbody>
並在<tbody>
中顯示所有<tr>
。我想要它像下面這樣:
<table id="qandatbl">
<thead>
<tr>
<th class="qid">Question No</th>
<th class="question">Question</th>
<th class="option">Option Type</th>
<th class="noofanswers">Number of Answers</th>
<th class="answer">Answer</th>
<th class="noofreplies">Number of Replies</th>
<th class="weight">Number of Marks</th>
<th class="image">Image</th>
<th class="video">Video</th>
<th class="audio">Audio</th>
</tr>
</thead>
<tbody>
<tr></tr>
<tr></tr>
<tr></tr>
</tbody>
</table>
我怎樣才能達到上述目的?
下面是控制<tbody>
和<tr>
的jquery代碼。
function insertQuestion(form) {
var $tbody = $("<tbody class='tbody'></tbody>");
var $tr = $("<tr class='optionAndAnswer'></tr>");
var $qid = $("<td class='qid'>" + qnum + "</td>");
var $question = $("<td class='question'></td>");
var $noofanswers = $("<td class='noofanswers'></td>");
var $options = $("<td class='option'></td>");
var $answer = $("<table class='answer'></table>");
var $replies = $("<td class='noofreplies'><div class='wrapper'></div></td>");
var $weight = $("<td class='weight'></td>");
var $image = $("<td class='image'></td>");
var $video = $("<td class='video'></td>");
var $audio = $("<td class='audio'></td>");
$('.gridTxt', context).each(function() {
var $this = $(this);
var $optionsText = $("<input type='text' class='gridTxtRow maxRow' readonly='readonly' /><span href='#' class='showGrid'>[Open Grid]</span>").attr('name',$this.attr('name'))
.attr('value',$this.val())
$options.append($optionsText);
$questionType = $this.val();
});
$('.numberAnswerTxt', context).each(function() {
var $this = $(this);
var $noofanswersText = '';
if ($questionType == 'True or False' || $questionType == 'Yes or No'){
$noofanswersText = $("<span class='naRow string' style='display: block;'>Only 1 Answer</span><input type='text' class='numberAnswerTxtRow answertxt' style='display: none;' onkeyup='numberKeyUp(this)' onkeypress='return isNumberKey(event)' onChange='getButtons()'>").attr('name', $this.attr('name')).attr('value', $this.val())
}else{
$noofanswersText = $("<span class='naRow string' style='display: none;'>Only 1 Answer</span><input type='text' class='numberAnswerTxtRow answertxt' style='display: block;' onkeyup='numberKeyUp(this)' onkeypress='return isNumberKey(event)' onChange='getButtons()'>").attr('name', $this.attr('name')).attr('value', $this.val())
}
$noofanswers.append($noofanswersText);
});
$('#questionTextArea').each(function() {
var $this = $(this);
var $questionText = $("<textarea onload='resizeTxt'></textarea>").attr('name',$this.attr('name'))
.attr('value',$this.val())
$question.append($questionText);
$tbody.append($tr);
$tr.append($qid);
$tr.append($question);
$tr.append($options);
$tr.append($noofanswers);
$tr.append($answer);
$tr.append($replies);
$tr.append($weight);
$tr.append($image);
$tr.append($video);
$tr.append($audio);
$('#qandatbl').append($tbody);
}
下面是HTML中挑選出<thead>
並且其中的jQuery <tbody>
和<tr>
將進入表:
<table id="qandatbl" align="center">
<thead>
<tr>
<th class="qid">Question No</th>
<th class="question">Question</th>
<th class="option">Option Type</th>
<th class="noofanswers">Number of Answers</th>
<th class="answer">Answer</th>
<th class="noofreplies">Number of Replies</th>
<th class="weight">Number of Marks</th>
<th class="image">Image</th>
<th class="video">Video</th>
<th class="audio">Audio</th>
</tr>
</thead>
</table>
你的代碼適合我。只有我看到的錯誤是我假設'var $ answer = $(「
除非你多次調用'insertQuestion' ......在這種情況下,當然你會有幾個'
'元素,因爲每個調用都會創建並附加一個新元素。 – 2012-01-22 01:39:58var $ answer實際上是唯一一個表,其他人是td,這是有原因的。我將更新我的代碼,其中包含一些.each函數,看看它是否仍然正確 – user1163005
回答
你可以只添加
<tbody>
到HTML:然後使用這個:
http://jsfiddle.net/QGBw3/1/
來源
2012-01-22 01:44:47
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