庫存缺貨的期限

Question

我差不多2年前發佈了以下問題，並收到了一個完美答案，但現在我需要擴展問題以獲取缺貨持續時間。這裏是原來的問題，併爲我提供答案：。

「我需要確定庫存的inStock和缺貨的模式

我有一個表，其中顯示項目，位置，庫存和日期我想看到如果存在某種情況下某個商品/地點缺貨並且隨時間推移而停止的時間，該文件包含三個星期的滾動數據，如果某個商品在三週內一直髮生缺貨或缺貨，那麼我需要要知道它有待進一步研究

如果庫存大於零，則庫存項目/庫位是庫存庫存爲零庫存或庫存庫存爲零庫存的庫存項目/庫位

感謝您的任何幫助。

的樣本數據

Item, location, inventory, date 
1243, 10,  2,   3/12/2012 
1243, 10,  0,   3/13/2012 
1243, 10,  -2,   3/14/2012 
1243, 10,  -2,   3/15/2012 
1243, 10,  4,   3/16/2012 

然後增加一個項目，位置，庫存，最新記錄。 「

我收到這個答案，它完美的作品。

SELECT item, 
    location, 
    SUM(CASE WHEN status = 'In Stock' AND prior_status = 'Out of Stock' 
      THEN 1 
      ELSE 0 
     END) moved_to_out_of_stock, 
    SUM(CASE WHEN status = 'Out of Stock' AND prior_status = 'In Stock' 
      THEN 1 
      ELSE 0 
      END) moved_to_in_stock 
    FROM (SELECT item, 
      location, 
      status, 
      lag(status) over (partition by item, location 
            order by dt) prior_status 
     FROM (SELECT item, 
        location, 
        (case when inventory <= 0 
         then 'Out of Stock' 
         else 'In Stock' 
        end) status, 
        dt 
       FROM your_table)) 
    GROUP BY item, location 

現在我希望能夠確定‘缺貨’每次出現的時間。許多天基本上是如何該項目的持續時間。，位置缺貨每次它一度脫銷

任何幫助深表感謝

編輯 這是我目前使用的查詢：

select ari.ITEM, x.LOCATION, MOVED_TO_OUT_OF_STOCK, MOVED_TO_IN_STOCK 
from (select item, location, 
SUM(CASE WHEN status = 'In Stock' AND prior_status = 'Out of Stock' 
       THEN 1 
       ELSE 0 
      END) 
moved_to_out_of_stock, 
SUM(CASE WHEN status = 'Out of Stock' AND prior_status = 'In Stock' 
       THEN 1 
       ELSE 0 
      END) 
moved_to_in_stock 
    FROM (select item, location, status, lag(status) 
    over (partition by item, location 
    order by repl_date) prior_status 
    FROM (select item, location,(CASE WHEN (stock_on_hand - demo_stock - non_sellable_qty) <='0'--subtract demo stock and non sellable qty 
    then 'Out of Stock' 
    else 'In Stock' 
    end) 
    status, repl_date 
    from repl_results)) 
    group by item, location) x, active_repl_items ari, 
    (select item, location, min(repl_date) as min_repl_date from repl_results 
    group by item, location)y, 
    (select item, location, repl_date, (STOCK_ON_HAND-DEMO_STOCK-NON_SELLABLE_QTY) AS NET_AVAIL from repl_results) z 
where (x.item = ari.item or x.item = ari.primary_pack_no) --to account for pack_items 
and x.item = y.item and x.item = z.item 
and x.location = y.location and x.location = z.location 
and y.min_repl_date = z.repl_date 
and x.location = ari.location 

Answer 1

以下是解決問題的方法。每次找到缺貨狀態時都會添加0/1標誌。然後做一個這個標誌的累計和。該累計總和按順序確定脫銷情況。當您通過累計總和累計時，您可以獲得脫銷條件的持續時間：

select item, location, ooi_grp, min(dt) as mindt, max(dt) as maxdt, 
     (max(dt) - min(dt) + 1) as duration 
from (select t.*, sum(startooi_flag) over (partition by item, location order by dt) as ooi_grp 
     FROM (SELECT item, location, status, 
        (case when lag(inventory) over (partition by item, location order by dt) > 0 and 
           inventory <= 0 
         then 1 else 0 
        end) as startooi_flag 
      FROM your_table 
      ) t 
    ) t 
where inventory <= 0 
group by item, location;