JOOQ：如何在複雜的Select語句中使用別名？

這裏是我的select語句JOOQ：如何在複雜的Select語句中使用別名？

SelectQuery<Record> selectQueryPayment = transaction.selectQuery(); 
    selectQueryPayment.addSelect(AccountPayment.ACCOUNT_PAYMENT.PAYMENT_NUMBER,AccountPayment.ACCOUNT_PAYMENT.PAYMENT_AMOUNT,AccountPayment.ACCOUNT_PAYMENT.PAYMENT_TYPE, 
        AccountPayment.ACCOUNT_PAYMENT.PAYMENT_DATE,AccountPayment.ACCOUNT_PAYMENT.PAYMENT_AMOUNT,AccountPayment.ACCOUNT_PAYMENT.PAYMENT_AMOUNT.subtract(AccountPayment.ACCOUNT_PAYMENT.AMOUNT_REFUNDED.add(AccountPayment.ACCOUNT_PAYMENT.AMOUNT_APPLIED)));

在這裏你可以看到一個複雜的一些計算

ACCOUNT_PAYMENT.PAYMENT_AMOUNT.subtract(AccountPayment.ACCOUNT_PAYMENT.AMOUNT_REFUNDED.add(AccountPayment.ACCOUNT_PAYMENT.AMOUNT_APPLIED))

如何爲這個創建別名選擇？然後從中獲取數據？

來源

2013-10-31 Subodh Joshi

好我得到了我們可以利用這個

AccountPayment.ACCOUNT_PAYMENT.PAYMENT_AMOUNT.subtract(AccountPayment.ACCOUNT_PAYMENT.AMOUNT_REFUNDED.add(AccountPayment.ACCOUNT_PAYMENT.AMOUNT_APPLIED)).as("OverPayment")

我們必須添加as("Alias Name")並獲得價值回，我們必須使用

 Result<Record> resultPayment = selectQueryPayment.fetch(); 
      for(Record record : resultPayment){ 
      feeAmount = resultPayment.getValues("OverPayment");

}

解決方案

來源

2013-10-31 10:36:04

JOOQ：如何在複雜的Select語句中使用別名？

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