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我已經建立了與Yii2查詢生成器下面的查詢:在Yii2結合GROUP_CONCAT DISTINCT與COUNT查詢
public function searchFilter() {
$query = (new Query())
->select([
'GROUP_CONCAT(DISTINCT(a.merk), ".", m.merk ORDER BY a.merk ASC) merk',
'GROUP_CONCAT(DISTINCT(b.brandstof) ORDER BY b.brandstof ASC) brandstof',
'GROUP_CONCAT(DISTINCT(a.bouwjaar) ORDER BY a.bouwjaar DESC) bouwjaar',
'GROUP_CONCAT(DISTINCT(k.kleur) ORDER BY k.kleur ASC) kleur',
'GROUP_CONCAT(DISTINCT(t.transmissie) ORDER BY t.transmissie ASC) transmissie',
])
->from('auto_new a')
->join('INNER JOIN', 'tbl_merken m', 'a.merk = m.merk_id') //Merk
->join('INNER JOIN', 'tbl_kleur k', 'a.kleur = k.kleur_id') //Kleur
->join('INNER JOIN', 'tbl_transmissie t', 'a.transmissie = t.transmissie_id') //Transmissie
->join('INNER JOIN', 'tbl_brandstof b', 'a.brandstof = b.brandstof_id'); //Brandstof
return $query;
}
這給了我下面的輸出:
但現在我想要在DISTINCT中的每個值後添加一個計數。但我不知道該怎麼做。
編輯 這是執行查詢
public function actionSearchfilter($ac) {
Yii::$app->response->format = Response::FORMAT_JSON;
$query = Car::searchFilter()->where(['a.ac' => $ac, 'a.flag' => '1'])->all();
return $query;
}
給我看一個正常的sql示例..所以我可以evaluete你的目標 – scaisEdge
你能再多一些代碼嗎? –