我試圖實現CLRS中描述的BFS算法。並具備以下條件:C++:初始化指針隊列時出現段錯誤
#include <iostream>
#include <list>
#include <queue>
#include <string>
#include <sstream>
using namespace std;
struct Node{
char colour;
int numNbr;
Node* parent;
int distance;
int* neighbours;
int* costs;
int name;
Node(int _numNbr,int _name){
name = _name;
colour = 'w';
parent = 0;
distance = -1;
neighbours = new int[_numNbr];
costs = new int[_numNbr];
numNbr = _numNbr;
}
};
list<Node*> bfs(Node** &nodes,int numNodes,int startNode) {
cout << "performing BFS\n";
for(int i = 0; i < numNodes;i++) {
nodes[i]->colour = 'w';
nodes[i]->parent = 0;
}
cout << "All nodes painted white" <<endl;
queue<Node*> q; // segfault occurs here
cout << "initialised a queue" << endl;
list<Node*> l;
cout << "initialised a list" << endl;
nodes[startNode]->colour = 'g';
nodes[startNode]->distance = 0;
q.push(nodes[startNode]);
Node* u;
Node* v;
while(!q.empty()){
u = q.front();
for(int i = 0;i < u->numNbr; i++) {
v = nodes[u->neighbours[i]];
if(v->colour == 'w'){
v->colour = 'g';
v->distance = (u->distance)+1;
v->parent = u;
q.push(v);
}
}
l.push_front(u);
u->colour = 'b';
q.pop();
}
return l;
}
int main(){
int nodeCount;
cin >> nodeCount;
cin.ignore();
Node** nodes = new Node*[nodeCount+1];
for(int i = 0; i < nodeCount; i++){
.... // build up the nodes in the adjacency list
}
list<Node*> l = bfs(nodes,nodeCount,1);
cout << "BFS of nodes\n";
for(list<Node*>::iterator it = l.begin();it != l.end();it++){
cout << (*it)->name << " ";
}
cout << endl;
return 0;
}
當我運行此不過,我只當隊列被初始化得到下面的輸出後跟一個segfault
:
[email protected]:~/Code/cpp/dijkstra$ ./dijkstra
3
1 2 1 3 1
2 3 1
3 1 1
performing bfs
All nodes painted white
Segmentation fault
我用下面的命令編譯:
g++ -Wall -o dijkstra dijkstra.cpp
使用調試器,做一個堆棧跟蹤。按照:http://stackoverflow.com/questions/3911814/c-in-g-segmentation-fault-when-not-using-pointers/3911873#3911873 – nsanders
如果你有一個segfault創建隊列容器,那麼最有可能堆已損壞。你有關於創建鄰接表的評論,但這可能是問題所在。你正在分配一個節點數組,但你是否還分配了單個節點? –
關於風格的評論:使用變量名「l」(小寫字母L)只會導致混淆(因爲每個人都會認爲它是「1」(數字1))。所以,請你幫個忙,用另一個名字。 –