我正在嘗試創建一個簡單的計算器,但是我使用的IDE不斷告訴我,我正在嘗試使用字符串執行數學運算。我嘗試將所有變量分配給雙打,但它沒有奏效。數學和變量問題 - Python 3.3
"""Calculator program"""
loop = 1 # 1 means loop; anything else means don't loop.
choice = 0 # This variable holds the user's choice in the menu
add1 = 0.0
add2 = 0.0
sub1 = 0.0
sub2 = 0.0
mul1 = 0.0
mul2 = 0.0
div1 = 0.0
div2 = 0.0
result = 0.0
while loop == 1:
# Print the options user has
print ("Welcome to calculator.py")
print ("your options are:")
print (" ")
print ("1) Addition")
print ("2) Subtraction")
print ("3) Multiplication")
print ("4) Division")
print ("5) Quit calculator.py")
print (" ")
#Perform the desired operation
choice = int(input("Choose your option: ").strip())
if choice == 1:
add1 = input()
add2 = input()
result = add1 + add2
print(add1, add2)
print (add1, "+", add2, "=", result)
elif choice == 2:
sub2 = input()
sub1 = input()
result = sub1 - sub2
print (sub1, "-", sub2, "=", result)
elif choice == 3:
mul1 = input("Multiply this: ")
mul2 = input("with this: ")
result = mul1 * mul2
print (mul1, "*", mul2, "=", result)
elif choice == 4:
div1 = input("Divide this: ")
div2 = input("by this: ")
result = div1/div2
print (div1, "/", div2, "=", result)
elif choice == 5:
loop = 0
print ("Thank-you for using calculator.py!")
@casperOne:這是不是很難說什麼是問。他是Python的新手。顯然,他不知道究竟應該問什麼。但答案很清楚。請重新提出問題,讓提問者有機會與世界交流。 – pepr 2013-02-28 18:44:48
「無效」符合含糊,模糊和不完整的定義。 – casperOne 2013-02-28 19:00:58
@casperone:感謝您關閉'模糊'問題,但我不明白它是如何模糊的。我是Python新手,這是我甚至試圖編寫的第一個程序。 '沒有工作'noes不適合曖昧。含糊不清:「對多個解釋開放。」在這種情況下,'沒有工作'表明我嘗試的解決方案無效,你可能想知道它是如何工作的,但它與手頭的問題無關。 – Xethaios 2013-03-04 15:54:20