如何在SQL Server 2005中只插入非重複的行？

Question

我試過以下。它不會插入任何新行，儘管沒有行也是重複的。爲什麼？我做錯了什麼？任何幫助的讚賞

 INSERT INTO TEMP_8 
    SELECT PASS_M, ENTRY_DT, EXIT_D, WORKED_HRS, 
      CONSECUTIVE_D = num -(SELECT max(num) 
            FROM TEMP_7 B 
            WHERE B.CONSEC <= A.CONSEC 
             AND B.GAP = 1 
             AND A.IC_N = B.IC_N) + 1 
    FROM TEMP_7 A 
    WHERE NOT EXISTS (SELECT * 
         FROM TEMP_8); 

更新：

PASS_M ENTRY_DT, EXIT_DT, WORKED_HRS 
peter 20/12/12 21/12/12 12 
Tom 20/12/12 21/12/12 10 
Tom 21/12/12 22/12/12 9 

這些都不重複。重複的是當name,entry_dt和exit_dt完全相同。

Answer 1

INSERT INTO TEMP_8 
SELECT PASS_M, ENTRY_DT, EXIT_D, WORKED_HRS, 
     CONSECUTIVE_D = num -(SELECT max(num) 
           FROM TEMP_7 B 
           WHERE B.CONSEC <= A.CONSEC 
            AND B.GAP = 1 
            AND A.IC_N = B.IC_N) + 1 
FROM TEMP_7 A 
WHERE NOT EXISTS (SELECT * 
        FROM TEMP_8 B 
        WHERE B.PASS_M = A.PASS_M 
        and B.ENTRY_DT = A.ENTRY_DT 
        and B.EXIT_D = A.EXIT_D); 

Answer 2

您需要過濾與在選擇數據如下存在：

INSERT INTO TEMP_8 
SELECT PASS_M, ENTRY_DT, EXIT_DT, WORKED_HRS, 
     CONSECUTIVE_D = num -(SELECT max(num) 
           FROM TEMP_7 B 
           WHERE B.CONSEC <= A.CONSEC 
            AND B.GAP = 1 
            AND A.IC_N = B.IC_N) + 1 
FROM TEMP_7 A 
WHERE NOT EXISTS (SELECT 1 
        FROM TEMP_8 T 
WHERE A.PASS_M=T.PASS_M AND A.ENTRY_DT=T.ENTRY_DT AND A.EXIT_DT=T.EXIT_DT);