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似乎無法弄清楚這一點。只需要2個oracle時間戳列之間的分鐘差異即可。如何從2個時間戳列中獲得分鐘數的差異?
END_TS START_TS
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11-NOV-13 01.52.14.000000 PM 11-NOV-13 01.51.14.000000 PM
11-NOV-13 02.20.47.000000 PM 11-NOV-13 02.19.47.000000 PM
18-NOV-13 12.44.54.000000 PM 18-NOV-13 12.34.02.000000 PM
22-NOV-13 12.02.09.000000 AM 22-NOV-13 12.02.08.000000 AM
我得到的結果的形式: DIFFERENCEINMINUTES ----------------- -------------------------------------------------- -------- +000000000 00:00:00.000000000 +000000000 00:00:00.000000000 +000000010 20:48:00.000000000 +000000000 00:24:00.000000000 +000000000 00:00:00.000000000 – KingKongFrog
增加了ROUND()以在十進制之後將分鐘舍入爲0。現在試試。 – Shiva