組通過在MySQL查詢

Question

兩個條件我有一個數據

+----+----------+-------+---------+ 
| id | date |loan_id|daily_amt| 
+----+----------+-------+---------+ 
| 1 |20-07-2014| 1 | 200 | 
| |   |  |   | 
| 2 |20-07-2014| 1 | 300 | 
| |   |  |   | 
| 3 |20-07-2014| 2 | 400 | 
| |   |  |   | 
| 4 |20-07-2014| 2 | 200 | 
| |   |  |   | 
| 5 |21-07-2014| 1 | 100 | 
+----+----------+-------+---------+ 

我需要每天daily_amt總每個loan_id在這個結構如下表dailyentry。如下所示。

+----+----------+-------+---------+ 
| id | date |loan_id|daily_amt| 
+----+----------+-------+---------+ 
| 1 |20-07-2014| 1 | 500 | 
| |   |  |   | 
| 3 |20-07-2014| 2 | 600 | 
| |   |  |   | 
| 5 |21-07-2014| 1 | 100 | 
+----+----------+-------+---------+ 

我試圖通過groub by date得到它。這樣下面，

select *,sum(daily_amt) from dailyentry group by date

此查詢結果被示出像下面。

+----+----------+-------+---------+--------------+ 
| id | date |loan_id|daily_amt|sum(daily_amt)| 
+----+----------+-------+---------+--------------+ 
| 1 |20-07-2014| 1 | 500 |  1100  | 
| |   |  |   |    | 
| 5 |20-07-2014| 1 | 100 |  100  | 
+----+----------+-------+---------+--------------+ 

我希望有人已經解決過這樣的問題了。請分享一些想法。

Answer 1

您是否嘗試過：

select *,sum(daily_amt) from dailyentry group by date, loan_id