PHP張貼<a href>導致插入錯誤

Question

我正在寫一個PHP文件，從表單中取值並將它們發佈到mysql數據庫。其中一個表格字段是指向點擊後播放的視頻的按鈕鏈接。如果我進入數據庫並手動添加鏈接，它會很好用。但是，我的PHP插入導致一個錯誤。請看看這段代碼：

$fileName = "video_".$id.".html"; 
$link = "<a href=\"javascript: void(0)\" onclick=\"MM_openBrWindow('videos/".$fileName."','','toolbar=no,location=no,status=no,menubar=no,scrollbars=no,resizable=yes,width=420,height=390')\"><button class=\"count\">Watch Video</button></a>"; 
$con=mysqli_connect("localhost","videomanager","password","my_database"); 
// Check connection 
if (mysqli_connect_errno()) 
    { 
    echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
    } 
$sql="INSERT INTO video_list (date, title, description, link) VALUES('$_POST[date]','".mysqli_real_escape_string($_POST['sermon'])."','".mysqli_real_escape_string($_POST['description'])."','$link')"; 
if (!mysqli_query($sql,$con)) 
    { 
    die('Error: ' . mysqli_error()); 
    } 
    echo "This video has been successfully added to the video database."; 
mysqli_close($con); 

如果我通過執行如下操作來查看$ link：echo $ link;死（）;它使用按鈕生成一個頁面，按鈕中的代碼看起來不錯。這是我如何試圖插入它？謝謝你的幫助！

Answer 1

你有很多錯誤

<?php 
$fileName = "video_".$id.".html"; 
$link  = "<a href=\"javascript: void(0)\" onclick=\"MM_openBrWindow('videos/".$fileName."','','toolbar=no,location=no,status=no,menubar=no,scrollbars=no,resizable=yes,width=420,height=390')\"><button class=\"count\">Watch Video</button></a>"; 
$con  = mysqli_connect("localhost","videomanager","password","my_database"); 

// Check connection 
if (mysqli_connect_errno()) 
    die('Failed to connect to MySQL: ' . mysqli_connect_error()); 

// Check param is set 
if(!isset($_POST['date'], $_POST['sermon'], $_POST['description'])) 
    die('Param Error'); 

// SQL Request 
$sql = sprintf("INSERT INTO video_list (date, title, description, link) VALUES('%s','%s','%s','%s')", 
     mysqli_real_escape_string($con, $_POST['date']), 
     mysqli_real_escape_string($con, $_POST['sermon']), 
     mysqli_real_escape_string($con, $_POST['description']), 
     mysqli_real_escape_string($con, $link) 
); 

// SQL execute 
$result = mysqli_query($con, $sql) or die('Error: ' . mysqli_error($con)); 

// Free result 
mysqli_free_result($result); 

// Close connection 
mysqli_close($con); 

echo "This video has been successfully added to the Kim Watt videos.";