此功能: for i in Selection:
cursor.execute(Query)
ydata[i] = [int(x[0]) for x in cursor.fetchall()]
提出: ValueError: invalid literal for int(): NULL if a null value is found.
我怎樣才能讓我的查詢返回零,而
我有以下查詢: SELECT products_categories.categoryID, name, COUNT(*) AS itemCount
FROM products_categories
LEFT JOIN products_to_categories ON products_to_categories.categoryID = products_categories.catego
我有一個腳本來查找列的最低值,但有些條目沒有值或其設置爲0,如果是這種情況我想ti找到下一個最低值。 這是我的sql命令。 $result = mysql_query("SELECT DISTINCT product_name, format, image_url, MIN(online_price), EAN FROM products where $searchstring and forma