SQL幫助。如何排列同一行上的值，將一列向上移動？

Question

我有問題讓列排隊，start_time是end_time之上的一行。

這是我的代碼：

SELECT B.NAME 
     ,MAX(case when DESCRIPTION = 'Green' then Final_Value end) as Start_Time 
     ,MAX(case when DESCRIPTION = 'Red' then Final_Value end) as End_Time 
      FROM mydata a 
      JOIN ref_val B 
      ON A.ref_res = B.ref_res  
     WHERE B.COMPANY = 'abc' 
     GROUP BY B.NAME 

這就是我想要得到

The result looks like this: 
    Name  Start_time    End_time   
1 John  5/6/15 6:30 
2 John2  5/7/15 4:30   5/6/15 8:30   
3 Ben   5/8/15 2:30   5/7/15 7:25 
4 Ben2  5/9/15 3:10   5/8/15 4:10 

I want it to look like this: 

    Name  Start_time    End_time    
1 John  5/6/15 6:30   5/6/15 8:30 
2 John2  5/7/15 4:30   5/7/15 7:25   
3 Ben   5/8/15 2:30   5/8/15 4:10 
4 Ben2  5/9/15 3:10   5/9/15 5:20 

Answer 1

使用窗口函數LEAD。在這種情況下，最直接的做法是將當前查詢嵌套爲已寫入，然後在外部查詢中應用分區。請參閱：

http://mysqlserverteam.com/mysql-8-0-2-introducing-window-functions/

Answer 2

一個模式會有所幫助，但我懷疑是驅動表不應該是mydata A，而是ref_val b，使集團通過與MAX更有意義。根據實際模式，我可能完全錯誤：

SELECT B.NAME 
    ,MAX(case when DESCRIPTION = 'Green' then Final_Value end) as Start_Time 
    ,MAX(case when DESCRIPTION = 'Red' then Final_Value end) as End_Time 
     FROM ref_val B 
     JOIN mydata A 
     ON A.ref_res = B.ref_res  
    WHERE B.COMPANY = 'abc' 
    GROUP BY B.NAME