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我正在嘗試提交表單,當您提交時,您會收回相同的頁面。我遇到的問題是,據我知道,我使用的將永遠是唯一取決於故事UrlGenerationException.php中的UrlGenerationException第17行:
我得到這個錯誤
UrlGenerationException在UrlGenerationException.php線蛞蝓17:缺少[Route:slug] [URI:stories/{slug}]所需的參數。
我的形式
@extends('templates::layouts.public')
@section('content')
@foreach($stories as $story)
{!! $story->title !!}
{!! $story->content !!}
@endforeach
{{ Form::open(array('url' => '/stories/'.$slug, 'id' => 'comment_form')) }}
<input type="hidden" name="comment_id" id="comment_id" value="">
<div class="form_group">
{{ Form::label('name', 'Name') }}
{{ Form::text('name', '' , array("class" => "form-control")) }}
</div>
<div class="form_group">
{{ Form::label('comment', 'Comment') }}
{{ Form::textarea('comment', '' , array("class" => "form-control")) }}
</div>
<div class="form_group submit_button">
{{ Form::submit('Submit', array("class" =>"btn btn-info submit", "role" => "button")) }}
</div>
{{ Form::close() }}
@stop
我的控制器功能
public function comment(Request $request, $slug)
{
$comments = new Comment();
$input = Input::all();
$validation = Validator::make($input, Comment::$rules);
if($validation->fails())
{
return redirect()->route('')
->withInput()
->withErrors($validation)
->with('message', 'There were validation errors');
}
if($validation->passes())
{
$comments->name = Input::get('name');
$comments->comment = Input::get('comment');
$data = array(
'name' => Input::get('name'),
'comment' => Input::get('comment')
);
Mail::send('templates::emails.comment', $data, function($message){
$message->to('[email protected]', Input::get('name'))->subject('A new comment was added');
});
$comments->save();
$comments = Comment::all();
return redirect()->route('slug');
}
}
我的路線
Route::post('/stories/{slug}', [
'uses' => '[email protected]',
'as' => 'comment'
]);
那麼,錯誤是很清楚的:你沒有正確地建立自己的路線。去這裏https://laravel.com/docs/5.4/routing,並學習如何正確地做到這一點。 – Amarnasan
從哪裏得到slu form的形狀? –