如何對最低值的數組列表對象進行排序？

Question

ArrayList <ShyForeignStockHolding> aithird = new ArrayList<ShyForeignStockHolding>(); 

ShyForeignStockHolding shyfrst = new ShyForeignStockHolding (shyPurchaseSharePrice, shyCurrentSharePrice, shyNumberOfShares, shyCompanyName, shyconversionRate1); 

aithird.add(shyfrst); 

我想Currentshare Price

Answer 1

排序ArrayList您可以使用對象的自定義Comparator，假設你正在使用雙爲shyCurrentSharePrice：

List<ShyForeignStockHolding> sFSH = new ArrayList<ShyForeignStockHolding>(); 
//add Your objects 
Collections.sort(sFSH, new Comparator<ShyForeignStockHolding>() { 
    @Override public double compare(ShyForeignStockHolding ssh1, ShyForeignStockHolding ssh2) { 
     return ssh1.shyCurrentSharePrice + shh2.shyCurrentSharePrice; //descending use - for Ascending 
    } 

}); 

Answer 2

與Java 8中，您現在可以輕鬆創建一個Comparator（完全避免匿名類）。由於這是按升序排列，因此您可以在該比較器上調用reversed()使其降序。

Comparator<ShyForeignStockHolding> comparator = Comparator.comparing((sh -> sh.getTheVarYouWantToCompareBy())).reversed(); 
aithird.sort(comparator);