的Oracle SQL語句中得到個月的兩個日期

我有一個表與起始日期和結束日期的Oracle SQL語句中得到個月的兩個日期

Table A 
    id | begin | end 
    ------------------------ 
    1 | 15-03-2014 | 06-05-2014 
    2 | 03-04-2014 | 31-04-2014

而且我需要選擇周beetween這些日期之間。結果是：

Result should return the rows: 
    id  | month | begin  | end 
    --------------------------------------------- 
    1  | 03/03/2014 | 15-03-2014 | 06-05-2014 
    1  | 04/03/2014 | 15-03-2014 | 06-05-2014 
    1  | 05/03/2014 | 15-03-2014 | 06-05-2014 
    1  | 06/03/2014 | 15-03-2014 | 06-05-2014 
    1  | 01/04/2014 | 03-04-2014 | 31-04-2014 
    ... 
    2  | 01/04/2014 | 03-04-2014 | 31-04-2014 
    2  | 02/04/2014 | 03-04-2014 | 31-04-2014 
    2  | 03/04/2014 | 03-04-2014 | 31-04-2014 
    2  | 04/04/2014 | 03-04-2014 | 31-04-2014 
    2  | 05/04/2014 | 03-04-2014 | 31-04-2014

或者幾個月：

id  | month | begin  | end 
    --------------------------------------------- 
    1  | 03/2014  | 15-03-2014 | 06-05-2014 
    1  | 04/2014  | 15-03-2014 | 06-05-2014 
    1  | 05/2014  | 15-03-2014 | 06-05-2014 
    2  | 04/2014  | 03-04-2014 | 31-04-2014

的選擇數週/數月可單獨不是所有在一個！

來源

2014-02-25 wasp256

'31-04-2014'是不是一個有效日期。 –

with i (id, month, begin_, end_) as (
    select 
     id, 
     trunc(begin_, 'mm') month, 
     begin_, 
     end_ 
    from 
     a 
    union all 
    select 
     id, 
     add_months(month, 1) month, 
     begin_, 
     end_ 
    from 
     i 
    where 
     add_months(month, 1) < end_ 
) 
select 
    id, 
    to_char(month, 'mm/yyyy') month, 
    begin_, 
    end_ 
from 
    i 
order by 
    id, 
    month;

來源

2014-02-25 10:11:21

select TRUNC(MONTHS_BETWEEN(end, begin)) as NumOfMonths, begin, end from TableA

來源

2014-02-25 09:11:51

'TRUNC（MONTHS_BETWEEN（end，begin））'只是給出了日期之間的monts數量，而不是每個月！ – wasp256

對於這些你必須創建存儲過程或函數 –

SQL> with t (id, begin#, end#) 
    2 as 
    3 (
    4 select 1, to_date('15-03-2014','DD-MM-YYYY'), to_date('06-05-2014','DD-MM-YYYY') from dual 
    5 union all 
    6 select 2, to_date('03-04-2014','DD-MM-YYYY'), to_date('30-04-2014','DD-MM-YYYY') from dual 
    7 ) 
    8 , 
    9 t1 (id, step#, begin#, end#) as 
10 (
11 select id, begin#, begin#, end# from t 
12 union all 
13 select id, step#+1, begin#, end# from t1 where step# < end# 
14 ) 
15 select * from t1 
16 order by id, step# 
17/

    ID STEP# BEGIN# END#              
---- -------- -------- --------             
    1 15.03.14 15.03.14 06.05.14             
    1 16.03.14 15.03.14 06.05.14             
    1 17.03.14 15.03.14 06.05.14             
    1 18.03.14 15.03.14 06.05.14             
    ............................ 
    1 02.05.14 15.03.14 06.05.14             
    1 03.05.14 15.03.14 06.05.14             
    1 04.05.14 15.03.14 06.05.14             
    1 05.05.14 15.03.14 06.05.14             
    1 06.05.14 15.03.14 06.05.14 

    2 03.04.14 03.04.14 30.04.14             
    2 04.04.14 03.04.14 30.04.14             
    2 05.04.14 03.04.14 30.04.14             
    2 06.04.14 03.04.14 30.04.14             
    2 07.04.14 03.04.14 30.04.14             
    ............................ 
    2 27.04.14 03.04.14 30.04.14             
    2 28.04.14 03.04.14 30.04.14             
    2 29.04.14 03.04.14 30.04.14             
    2 30.04.14 03.04.14 30.04.14 




SQL> with t (id, begin#, end#) 
    2 as 
    3 (
    4 select 1, to_date('15-03-2014','DD-MM-YYYY'), to_date('06-05-2014','DD-MM-YYYY') from dual 
    5 union all 
    6 select 2, to_date('03-04-2014','DD-MM-YYYY'), to_date('30-04-2014','DD-MM-YYYY') from dual 
    7 ) 
    8 , 
    9 t1 (id, step#, begin#, end#) as 
10 (
11 select id, begin#, begin#, end# from t 
12 union all 
13 select id, step#+1, begin#, end# from t1 where step# < end# 
14 ) 
15 select unique id, to_char(trunc(step#,'MM'),'MM/YYYY') step#, begin#, end# from t1 
16 order by id, step# 
17/

    ID STEP# BEGIN# END#              
---- ------- -------- --------             
    1 03/2014 15.03.14 06.05.14             
    1 04/2014 15.03.14 06.05.14             
    1 05/2014 15.03.14 06.05.14             
    2 04/2014 03.04.14 30.04.14

來源

2014-02-25 10:03:05

的Oracle SQL語句中得到個月的兩個日期

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