找到矩陣的所有元素等於座標（i + j）的總和

Question

我可以掃描矩陣並確定大小，但輸出爲空白。

這裏是我的代碼：

int createTripplesArrayAndList(int** mat, int row, int colum, Tripple **arr, Node** ls) { 
    int i, j, count=0, k = 0; 
    Node* head = *ls; 
    Node* tmp=NULL; 

    //count how many elements would be in the required array\list 
    for (i = 0; i < row; i++) { 
     for (j = 0; j < colum; j++) { 
      if (mat[i][j] == i + j) { 
       count++; 
      } 
     } 
    } 

    //going over the matrix and add the relevant elements to the array and to the list 
    (*arr) = (Tripple*)calloc(count, sizeof(Tripple)); 
    for (i = 0; i < row; i++) { 
     for (j = 0; j < colum; j++) { 
      if (mat[i][j] == i + j) { 
       //add element to array 
       (*arr)[k].argument = mat[i][j]; 
       (*arr)[k].i = i; 
       (*arr)[k].j = j; 

       //add element to the list 
       if (!head) { 
        tmp = (Node*)malloc(sizeof(Node)); 
        tmp->value = (*arr)[k]; 
        tmp->next = NULL; 

        head = tmp; 
       } else { 
        Node *new_node = (Node*)malloc(sizeof(Node)); 
        new_node->value = (*arr)[k]; 
        new_node->next = NULL; 
        head->next = new_node; 
        head = new_node; 
       } 
       k++; 
      } 
     } 
    } 

    *ls = tmp; 
    return count; 
} 

void printTrripleArrAndList(Tripple* arr, int n, Node** ls) { 
    int i, j; 
    Node* curr = *ls; 

    printf("The tripple list is: "); 
    while (curr != NULL) { 
     printf("%d+%d=%d ->", curr->value.i, curr->value.j, curr->value.argument); 
     curr = curr->next; 
    } 

    printf("\nThe tripple array is: "); 
    for (i = 0; i < n; i++) { 
     printf("%d+%d = %d\n", arr[i].i,arr[i].j,arr[i].argument); 
    } 
} 

int ** createMat(int*n,int*m) { 
    int** mat = NULL; 
    int i, j, row, column; 

    //allocate and the matrix 
    printf("please enter size of row and colum: "); 
    scanf("%d%d", &row, &column); 
    mat = (int**)calloc(row, sizeof(int*)); 
    for (i = 0; i < row; i++) { 
     mat[i] = (int*)calloc(column, sizeof(int)); 
    } 

    //fill the matrix 
    printf("enter numbers for the matrix: "); 
    for (i = 0; i < row; i++) { 
     for (j = 0; j < column; j++) { 
      scanf("%d", &mat[i][j]); 
     } 
    } 

    *n = row; 
    *m = column; 

    return mat; 
} 

我曾經碰到一個錯誤說類型節點*的值不能被分配到類型列表的實體*，所以我不得不他們都更改爲節點*的問題區域爲：

head-> next = new_node;

and：

curr = curr-> next;

請幫忙。

#include <stdio.h> 
#include <stdlib.h> 
#include <math.h> 
#define M 2 
#define N 3 
#define R 4 

typedef struct Tripple { 
    int i; 
    int j; 
    int argument; 
} Tripple; 

typedef struct Node { 
    Tripple value; 
    struct Node* next; 
} Node; 

int* powerArray(int n); 
void printPowArr(int* p, int n); 
int** MatrixMultiplication(int firstMat[M][N], int secondMat[N][R]); 
void printMatrix(int** p); 
int createTripplesArrayAndList(int** mat, int row, int colum, Tripple **arr, Node** ls); 
void printTrripleArrAndList(Tripple* arr, int n, Node** ls); 
int** createMat(int* n, int*m); 

這是我的主：

void main() { 
    int *p; 
    int** newMat; 

    int p1[M][N] = { { 1, 4, 2 }, { 0, 3, 1 } }; 
    int p2[N][R] = { { 1, 3, 1, 4 }, { 0, 2, 6, 4 }, { 4, 1, 0, 7 } }; 
    int **mat=NULL; 
    int count; 
    int n = 0, m = 0, i = 0, j = 0; 
    p = powerArray(10); 
    printPowArr(p, 10); 



    newMat = MatrixMultiplication(p1, p2); 
    printMatrix(newMat); 


    Tripple* arr=NULL; 
    Node* ls=NULL; 
    mat=createMat(&n,&m); 

    count = createTripplesArrayAndList(mat, n, m, &arr, &ls); 
    printTrripleArrAndList(arr, count, &ls); 
    system("pause"); 
} 

Answer 1

您都指向這兩個頭部和頭戴式>旁邊new_node！這是荒謬的。刪除head-> next = new_node。