獲取列表分配索引超出範圍

Question

不確定它爲什麼超出範圍。餘設置的範圍從0到5 這是我的代碼

class Car(object): 
    def __init__ (self, price, speed, fuel, mileage): 
     self.price = price 
     self.speed = speed 
     self.fuel = fuel 
     self.mileage = mileage 
     self.price = price 
     if price > 1000: 
      self.tax = 15 
     else: 
      self.tax = 12 
    def displayAll(self): 
     print "Price: " + str(self.price) 
     print "Speed: " + str(self.speed) 
     print "Fuel: " + str(self.fuel) 
     print "Mileage: " + str(self.mileage) 
     print "Tax: 0." + str(self.mileage) 

auto = [5] 
for car in range(0,5): 
    price = input("How much does the car cost? ") 
    speed = input("Mile per hour? ") 
    mileage = input("Mile per gallon? ") 
    fuel = raw_input("How much fuel? ") 
    print car 
    auto[car] = Car(price, speed, fuel, mileage) 

Answer 1

當那是因爲你剛剛創建其中包含一個元素5的列表。編寫此代碼的更好方法可能是

auto = [] 
for car in range(0,5): 
    price = input("How much does the car cost? ") 
    speed = input("Mile per hour? ") 
    mileage = input("Mile per gallon? ") 
    fuel = raw_input("How much fuel? ") 
    print car 
    auto.append(Car(price, speed, fuel, mileage)) 

Answer 2

自動被一個條目的矩陣，即數字5，即[5]。你希望它是一個有5個條目的矩陣。

Answer 3

您可以設置自動向auto=[5]，但它應該是auto=[None]*5或auto=range(5)

否則你創建長度爲1的列表，並會得到一個出界失誤調用auto[car]