2017-02-09 39 views
0
SELECT u.id, 
      'Shift' AS which, 
      se.created_at 
    FROM users AS u 
    JOIN schedule_elements AS se ON se.owner_id = u.id 
    UNION ALL 
      (SELECT u.id, 
         'Like' AS which, 
         ll.created_at 
      FROM users AS u 
      JOIN likes AS ll ON ll.owner_id = u.id 
      UNION 
      SELECT u.id, 
         'Comment' AS which, 
         cm.created_at 
      FROM users AS u 
      JOIN comments AS cm ON cm.owner_id = u.id) 
    ORDER BY ID DESC , created_at DESC 


The output looks like: 
id, which, created_at 
555, shift, <date> 
555, shift, <date> 
555, comment, <date> 
555, shift, <date> 
555, like, <date> 
333, shift, <date> 
333, shift, <date> 
333, comment, <date> 
333, shift, <date> 
111, like, <date> 
111, shift, <date> 
111, shift, <date> 

輸出具有5個條目ID 555,和4 333我要過濾這個查詢,使得我只有頂部3條目555,頂部3 333,等等。PostgreSQL的限制柱至3%的值

回答

0

使用限制條款https://www.postgresql.org/docs/current/static/queries-limit.html

(SELECT u.id,'Shift' AS which,se.created_at 
    FROM users AS u 
    JOIN schedule_elements AS se ON se.owner_id = u.id ORDER BY u.id DESC , u.created_at DESC LIMIT 3) 
    UNION 
    (SELECT u.id,'Like' AS which,ll.created_at 
    FROM users AS u 
    JOIN likes AS ll ON ll.owner_id = u.id ORDER BY u.id DESC , u.created_at DESC LIMIT 3) 
    UNION 
    (SELECT u.id,'Comment' AS which,cm.created_at 
    FROM users AS u 
    JOIN comments AS cm ON cm.owner_id = u.id ORDER BY u.id DESC , u.created_at DESC LIMIT 3) 
+0

看起來像這個查詢不會工作 - 你可以使用LIMIT只用於整個語句(所有3聯合)。甚至它的作品,它會顯示每個SELECT 3項目不是所有。 –

+0

看起來像它在這裏工作http://stackoverflow.com/questions/1415328/combining-union-and-limit-operations-in-mysql-query – pottedmeat7

+0

這是完全不同的任務。每兩家不同的公司需要10條記錄。在這裏 - 最後3次對用戶+他們的評論和喜歡的操作。 –

0

也許你需要的是這樣的。對於CTE中的p,我使用您的查詢。在p2中,我通過窗口函數爲所有行設置了row_number,之後每個用戶只能顯示第一個/最後一個3。

WITH p AS (
    SELECT u.id, 
      'Shift' AS which, 
      se.created_at 
    FROM users AS u 
    JOIN schedule_elements AS se ON se.owner_id = u.id 
    UNION ALL 
    SELECT u.id, 
      'Like' AS which, 
      ll.created_at 
    FROM users AS u 
    JOIN likes AS ll ON ll.owner_id = u.id 
    UNION ALL 
    SELECT u.id, 
     'Comment' AS which, 
     cm.created_at 
    FROM users AS u 
    JOIN comments AS cm ON cm.owner_id = u.id 
), p2 AS (
    SELECT *, 
     row_number() OVER (PARTITION BY id ORDER BY created_at DESC) AS rank 
    FROM p 
    WHERE which IS NOT NULL 
) 
SELECT id, which, created_at --, rank 
FROM p2 
WHERE rank <= 3 
ORDER BY ID DESC , created_at DESC; 
+0

如果我的回答對您有幫助,請將您的問題標記爲已解決並投票給我。謝謝 –