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Question

我有兩個人，用戶222和用戶5555之間的消息會話的MySQL選擇數據的解決方案，它顯示是這樣的：

Conversation-ID 1, Message-ID 5, User-ID 222: "Oh, and I'm happy about that!" 
Conversation-ID 1, Message-ID 4, User-ID 222: "And bought me a new car." 
Conversation-ID 1, Message-ID 3, User-ID 222: "I just won some money!" 
Conversation-ID 1, Message-ID 2, User-ID 5555: "Fine, how are you?" 
Conversation-ID 1, Message-ID 1, User-ID 222: "Hi there, how are you?" 

現在我正在尋找在PHP的解決方案/ MySQL的只顯示來自用戶ID 222的消息，直到從用戶ID 5555。

消息的結果應該是：

Conversation-ID 1, Message-ID 5, User-ID 222: "Oh, and I'm happy about that!" 
Conversation-ID 1, Message-ID 4, User-ID 222: "And bought me a new car." 
Conversation-ID 1, Message-ID 3, User-ID 222: "I just won some money!" 

其實我有

"SELECT * FROM table_conversations WHERE conversation_id='1' and user_id !='5555' ORDER BY message_id DESC"

當然這將顯示我的用戶ID 222.我想是只有最後無應答消息從用戶ID 222

什麼的所有消息，但是否有任何命令或解決方案在php + mysql中獲得這個結果，也適用於所有其他會話？

Answer 1

假設消息id表示消息的順序：

select * 
from table_conversation c 
where user_id = 222 and 
     message_id > (select max(message_id) from table_conversation c2 where user_d = 555);