1
的陣列可以說，我初始化信號量的兩個全局陣列，索引到信號量
semaphore empty[someNum];
和
semaphore full[someNum];
和someNum被初始化爲
const int someNum = 3;（全局）
我將有一個名爲init()的方法，裏面是一個for-loop來幫助索引這些數組。
for (index=0; index<someNum; index++) num[index]=0;
我的目標是在陣列中使用的命令一樣wait和signal一定的信號量，例如，如果num是滿的，那麼我不希望我的製片人將值放入它。
裏面的init()我知道我需要初始化循環體中的所有信號量。到目前爲止，我已經嘗試
empty[index] = create_semaphore(1)
full[index] = create_semaphore(0)
和裏面的我想瓶坯wait和signal我試過例如
wait(empty) ;
行動的方法，但我回來錯誤。我知道這是因爲我使用數組的名稱而不是特定的信號量。
所以我的問題是，我如何正確索引到我的for-loop我的陣列指定一個信號量？
感謝您的任何和所有輸入！如果您有任何問題，請隨時要求澄清！請耐心等待，信號量對我來說是一個新概念。
注意
create_semaphore存在於這一個隸屬於另一個程序的命令。
編輯
foodPass.cpp
#include <iostream>
#include <sched.h>
#include <time.h>
#include <pthread.h>
#include <string>
#include "sem.h"
using namespace std ;
/* ######################################## */
/* Misc Data Types */
/* ######################################## */
/* A data type - a struct with an int field
to represent a child ID at the program level. */
struct threadIdType
{
int id ;
};
/* ######################################## */
/* Global Variables */
/* ######################################## */
//const int numTrivets = 6 ;
const int numTrivets = 3 ;
const int numDiners = numTrivets - 1 ;
const int maxDishNames = 13 ;
//const int numDishNames = 13 ;
const int numDishNames = 5 ;
int trivet[numTrivets] ;
string dishName[maxDishNames];
/* Here declare the semaphores and other variables you will
need to synchronize threads. */
sim_semaphore empty[numTrivets] ;
sim_semaphore full[numTrivets] ;
/* child_t are global variables to represent the
dynamically-created threads. */
pthread_t child_t[numTrivets] ;
/* ######################################## */
/* "Special" Global Variables */
/* ######################################## */
/* Code in sem.cpp "expects" the two variables below to be here.
This particular program does not use "checking." */
/* "Checking" is just a flag that you set to 1 if you want lots of
debugging messages and set to 0 otherwise. The semaphore code in
sem.cpp imports "checking". Therefore the semaphore operations
will write lots of messages if you set checking=1. */
int checking ;
/* In some programs, we use the "stdoutLock" variable declared below to
get intelligible printouts from multiple concurrent threads that write
to the standard output. (There has to be something to prevent the
output of the threads from interleaving unintelligibly on the standard
output, and we can't use semaphores if the semaphore code is writing
messages too.)
To print a message to standard output, a thread first locks standard
output, then writes, then unlocks standard output. See files sem.cpp
or conc.cpp for examples of code that write messages in this manner.
WARNING: DON'T change how the locking of standard output is done
until you've thought a WHOLE lot about the consequences. In
particular, using semaphores to do the job of stdoutLock can cause
"infinite recursion" under certain circumstances. The reason is that
the semaphore code itself imports "stdoutLock" and writes messages
when the "checking" variable is set to 1. */
pthread_mutex_t stdoutLock ;
/* ################################################## */
/* init */
/* ################################################## */
void init()
{
int index ;
srandom(time((time_t *) 0)); /* INITIALIZE RANDOM NUMBER GENERATOR */
checking = 0 ;
/* Initialize the "special lock" that is used only to get
exclusive access to the screen. */
if (0!=pthread_mutex_init(&stdoutLock, NULL))
{ cout << "MUTEX INITIALIZATION FAILURE!" << endl;
exit(-1) ;}
/* Initialize the trivets to indicate that each contains "no
dish." */
for (index=0; index<numTrivets; index++) trivet[index]=0;
/* Here initialize the semaphores and other variables you use
for synchronization. */
for (index=0; index<numTrivets; index++) full[index] = create_sim_sem(0) ;
for (index=0; index<numTrivets; index++) empty[index] = create_sim_sem(1) ;
/* Give some mnemonic names to the dishes. The first name is
used for an empty trivet. The last name denotes the check
(bill) for the meal. This is coded so no changes are needed
here as long as the value of "numDishNames" is between 2 and
13. */
dishName[0]="no dish";
dishName[1]="vegetable soup" ;
dishName[2]="bread and butter" ;
dishName[3]="beets and chickpeas" ;
dishName[4]="hardboiled eggs" ;
dishName[5]="calf tongue" ;
dishName[6]="baked potato" ;
dishName[7]="string beans" ;
dishName[8]="rack of lamb" ;
dishName[9]="salad" ;
dishName[10]="coffee" ;
dishName[11]="flan" ;
dishName[numDishNames-1]="check" ;
}
/* ################################################## */
/* DelayAsMuchAs */
/* ################################################## */
void delayAsMuchAs (int limit)
{
int time, step;
time=(int)random()%limit;
for (step=0;step<time;step++) sched_yield() ;
}
/* ################################################## */
/* Server */
/* ################################################## */
/*
The mother thread spawns a child thread that executes this
function. This function carries out the job of the server
at the restaurant.
*/
void * Server(void * ignore)
{
int i, j, delayLimit=100 ;
for (i=1; i<numDishNames; i++)
{
/* I delay a random time before I "feel like" placing
another dish on the table.*/
delayAsMuchAs(delayLimit);
/* When the trivet is available, I place the dish on the
trivet to my right. */
/* Here do a synchronization task. One thing you need to
do is be sure that you are not going to place a dish on
a trivet that alreay has a dish on it. *DO NOT* just
busy-wait until you see that the trivet is empty. */
wait_sem(empty[i]) ;
trivet[0]=i; // put dish #i onto trivet #0
pthread_mutex_lock(&stdoutLock) ;
cout << "Server places " << dishName[trivet[0]]
<< " on trivet #0." << endl ;
pthread_mutex_unlock(&stdoutLock);
/* Here you may want to a synchronization task --
something that "opens the door" for diner #0 to get
access to the new dish. */
signal_sem(full[i]) ;
}
pthread_exit ((void *)0) ;
}
/* ################################################## */
/* Diner */
/* ################################################## */
/*
The mother thread spawns child threads that execute this
function. This function carries out the job of one of the
diners at the restaurant.
*/
void * Diner(void * postnPtr)
{
/* Type cast the parameter to recover "position" -- which
tells me the position at which I am seated at the
table. */
int position = ((threadIdType *)(postnPtr))->id ;
int i, j, delayLimit=100 ;
for (i=1; i<numDishNames; i++)
{
/* I delay a random time before I "feel like" picking up the next
dish.*/
delayAsMuchAs(delayLimit);
/* When available, I pick up the next new dish on my left. */
/* Here do a synchronization task. One thing you need to
do is be sure that there is a new dish on the trivet to
your left now, and that the person on your left has
"let go" of it. */
wait_sem(full[i]);
/* I declare what I am doing */
pthread_mutex_lock(&stdoutLock) ;
cout << "Diner number "<< position ;
if (i<numDishNames-1) cout << " enjoys ";
else if (position<numDiners-1) cout << " examines " ;
else cout << " examines and pays " ;
cout << dishName[trivet[position]] << endl ;
pthread_mutex_unlock(&stdoutLock);
/* I delay a random time to simulate the time it takes for me to
serve myself some of what is on the dish -- or look at the
check. */
delayAsMuchAs(delayLimit);
/* When available, I place the dish on the trivet to my right. */
/* Here do a synchronization task. One thing you need to
do is be sure that the trivet on your right does not
have a dish on it now.*/
wait_sem (empty[i]);
pthread_mutex_lock(&stdoutLock) ;
cout << "Diner number "<< position << " moves "
<< dishName[trivet[position]] << " from trivet #"
<< position << " to trivet #" << position+1 << endl;
pthread_mutex_unlock(&stdoutLock);
/* transfer the dish on my left to trivet on my right */
trivet[position+1]=trivet[position] ;
/* mark trivet on my left as empty */
trivet[position]=0;
/* Here do a synchronization task. You have transferred a
dish from your left to your right. The person on your
left will need to find out that the trivet on your left
is now empty. The person on your right will need to
find out that the trivet on your right now has a new
dish on it. */
signal_sem(empty[i]);
signal_sem(full[i]);
}
delete((threadIdType *)(postnPtr)) ;
pthread_exit ((void *) 0) ;
}
/* ################################################## */
/* Busser */
/* ################################################## */
/*
The mother thread spawns children and then executes this
function. This is convenient because this function should
be the last to exit. This function carries out the job of
the busser at the restaurant.
*/
void * Busser (void * ignore)
{
int i, j, delayLimit=100 ;
for (i=1; i<numDishNames; i++)
{
/* I delay a random time before I "feel like" bussing another
dish.*/
delayAsMuchAs(delayLimit);
/* When another dish is on the trivet to my right I remove it. */
/* Here do a synchronization task. One thing you need to
do is be sure that there is a new dish on the trivet to
your left now, and that the person on your left has
"let go" of it. */
wait_sem (full[i]) ;
pthread_mutex_lock(&stdoutLock) ;
cout << "Busser removes "
<< dishName[trivet[numTrivets-1]] << " from trivet #"
<< numTrivets-1<< "." << endl ;
pthread_mutex_unlock(&stdoutLock);
trivet[numTrivets-1]=0; // remove the dish.
/* Here do a synchronization task. The person on your left
will need to find out that the trivet on your left is
now empty. */
signal_sem (empty[i]);
}
return ignore ;
}
/* ################################################## */
/* Main */
/* ################################################## */
int main()
{
init();
cout << endl << endl;
cout << "Welcome to the restaurant!" << endl ;
cout << numDiners << " will be dining." << endl ;
cout << "The meal will consist of " << numDishNames-2
<< " dishes." << endl;
cout << "Bon appetite!" << endl ;
cout << endl << endl;
int i;
/* This is a pointer to a struct that contains an int
field - it is a convenient data type to use as the
parameter to the child function. */
threadIdType * idPtr ;
for (i=0; i<numDiners; i++)
{
/* This records the current index as this child's ID */
idPtr = new threadIdType ;
idPtr->id = i ;
if (0!=pthread_create(&child_t[i], NULL, Diner, (void *) idPtr))
{cout << "THREAD CREATION FAILURE!" << endl; exit(-1) ;}
if (0!=pthread_detach(child_t[i]))
{cout << "THREAD DETACHMENT FAILURE!" << endl ; exit(-1) ;}
}
if (0!=pthread_create(&child_t[numDiners], NULL, Server, (void *) 0))
{cout << "THREAD CREATION FAILURE!" << endl; exit(-1) ;}
if (0!=pthread_detach(child_t[numDiners]))
{cout << "THREAD DETACHMENT FAILURE!" << endl ; exit(-1) ;}
Busser((void *) 0) ;
cout << endl << endl;
cout << "Thank you for coming!" << endl ;
cout << endl << endl;
return 0 ;
}
你在用什麼庫？如果你想等待一個特定的信號量，那麼你將不得不給它的索引。我不確定那就是你想要的。 POSIX信號量基於一個計數器，所以如果我正確理解你的話，可以通過一個單一的信號量來初始化爲正確的值。 – ChiefTwoPencils
好的，我將我的庫添加到了我的編輯 – Junikin
好吧，我想你知道直接問題的答案，即你無法將數組作爲sem傳遞。如果你確定自己有正確的實現，那麼就像遍歷它們並單獨等待它們一樣簡單。但那些阻止電話，所以我不願意提出更多的建議，而沒有看到你在做什麼。 – ChiefTwoPencils