0
我需要渲染一個圖形,但我每2米獲取一個數據。 爲了順利我的渲染,我想完成缺失數據每個奇數米,與 - next和prev關鍵 之間的深度 - - 同日 平均值之間的未來和prev關鍵在陣列的next和prev值之間插入平均值(每奇數)
我的foreach看起來像
foreach ($datas as $data) {
$chartline[] = array(
'date' => $data->date,
'depth' => $data->z,
'value' => round($data->value, 2)
);
}
的var_dump顯示:
0 =>
array (size=3)
'date' => string '2014-07-23 14:30:00' (length=19)
'depth' => float 2
'value' => float 23.45
1 =>
array (size=3)
'date' => string '2014-07-23 14:30:00' (length=19)
'depth' => float 4
'value' => float 20.48
2 =>
array (size=3)
'date' => string '2014-07-23 14:30:00' (length=19)
'depth' => float 6
'value' => float 19.76
3 =>
array (size=3)
'date' => string '2014-07-23 14:30:00' (length=19)
'depth' => float 8
'value' => float 18.78
4 =>
array (size=3)
'date' => string '2014-07-23 14:30:00' (length=19)
'depth' => float 10
'value' => float 17.9
5 =>
array (size=3)
'date' => string '2014-07-23 14:30:00' (length=19)
'depth' => float 12
'value' => float 17.04
6 =>
array (size=3)
'date' => string '2014-07-23 14:30:00' (length=19)
'depth' => float 14
'value' => float 16.71
7 =>
array (size=3)
'date' => string '2014-07-23 14:30:00' (length=19)
'depth' => float 16
'value' => float 16.25
,我想轉化爲:
0 =>
array (size=3)
'date' => string '2014-07-23 14:30:00' (length=19)
'depth' => float 1
'value' => float 23.45
1 =>
array (size=3)
'date' => string '2014-07-23 14:30:00' (length=19)
'depth' => float 2
'value' => float 23.45
2 =>
array (size=3)
'date' => string '2014-07-23 14:30:00' (length=19)
'depth' => float 3
'value' => float (AVERAGE BETWEEN 23.45 the previous key AND 20.48 the next key)
3 =>
array (size=3)
'date' => string '2014-07-23 14:30:00' (length=19)
'depth' => float 4
'value' => float 20.48
4 =>
array (size=3)
'date' => string '2014-07-23 14:30:00' (length=19)
'depth' => float 5
'value' => float (AVERAGE BETWEEN 20.48 the previous key AND 17.9 the next key)
5 =>
array (size=3)
'date' => string '2014-07-23 14:30:00' (length=19)
'depth' => float 6
'value' => float 17.9
.
.
.
.
.
如何添加我需要的值?
如果您有任何想法或提示!
爲什麼會變成這樣平滑線條的平均?如果您想要平滑要繪製曲線的線條,但仍然需要繪製相同的直線,但需要考慮多個數據點,並且應該生成比原始輸入更多的新點。讓我知道你是否感興趣(基本思路是映射每個現有點的增量值,然後根據會導致的轉換點添加新點,並重復N次,其中N至少爲2(否則它會看起來鋸齒))。 – scragar